如何使用PhoneGap的显示Android手机上摄像头

如何使用PhoneGap的显示Android手机上摄像头

本文介绍了如何使用PhoneGap的显示Android手机上摄像头的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

限时删除!!

我想用Android手机上的PhoneGap捕获图像。我尝试code PhoneGap的发布页面上,但相机不会出现。任何帮助是AP preciated.Thank你了。

这是显示我的手机上

 <!DOCTYPE HTML>
< HTML和GT;
  < HEAD>
    <标题>捕获照片< /标题>    <脚本类型=文/ JavaScript的字符集=utf-8SRC =科尔多瓦-1.6.0.js>< / SCRIPT>
    <脚本类型=文/ JavaScript的字符集=utf-8>    VAR pictureSource; //图片来源
    VAR destinationType; //设置返回值的格式    //等待科尔多瓦与设备连接
    //
    document.addEventListener(deviceready,onDeviceReady,FALSE);    //科尔多瓦是随时可以使用!
    //
    功能onDeviceReady(){
        pictureSource = navigator.camera.PictureSourceType;
        destinationType = navigator.camera.DestinationType;
    }    //如果照片是成功检索调用
    //
    功能onPhotoDataSuccess(为imageData){
      //取消注释查看的base64 EN codeD图像数据
      //执行console.log(为imageData);      //获取图像句柄
      //
      变种smallImage =的document.getElementById('smallImage');      //取消隐藏图像元素
      //
      smallImage.style.display =块;      //显示所拍摄的照片
      //内联CSS规则是用来调整图像大小
      //
      smallImage.src =数据:图像/ JPEG; BASE64,+为imageData;
    }    //如果照片是成功检索调用
    //
    功能onPhotoURISuccess(imageURI){
      //取消注释查看图像文件URI
      //执行console.log(imageURI);      //获取图像句柄
      //
      变种largeImage =的document.getElementById('largeImage');      //取消隐藏图像元素
      //
      largeImage.style.display =块;      //显示所拍摄的照片
      //内联CSS规则是用来调整图像大小
      //
      largeImage.src = imageURI;
    }    //一个按钮将调用这个函数
    //
    功能capturePhoto(){
      //将图片使用设备的摄像头和图像检索为base64-CN codeD字符串
      navigator.camera.getPicture(onPhotoDataSuccess,onFail,{质量:50,
        destinationType.DATA_URL});
    }    //一个按钮将调用这个函数
    //
    功能capturePhotoEdit(){
      //将图片使用设备的摄像头,让编辑和图像检索为base64-CN codeD字符串
      navigator.camera.getPicture(onPhotoDataSuccess,onFail,{质量:20,allowEdit:真实,
        destinationType.DATA_URL});
    }    //一个按钮将调用这个函数
    //
    功能getPhoto(源){
      //从指定源中检索图像文件位置
      navigator.camera.getPicture(onPhotoURISuccess,onFail,{质量:50,
        destinationType:destinationType.FILE_URI,
        sourceType的:源});
    }    //调用如果有什么不好的事情发生。
    //
    功能onFail(消息){
      警报('因为失败:'+消息);
    }    < / SCRIPT>
  < /头>
  <身体GT;
    <按钮的onclick =capturePhoto();>捕获照片< /按钮> < BR>
    <按钮的onclick =capturePhotoEdit();>捕获编辑照片及LT; /按钮> < BR>
    <按钮的onclick =getPhoto(pictureSource.PHOTOLIBRARY);肽从图片库< /按钮>< BR>
    <按钮的onclick =getPhoto(pictureSource.SAVEDPHOTOALBUM);>从相册和LT; /按钮>< BR>
    < IMG风格=显示:无;宽度:60像素,高度:60像素; ID =smallImageSRC =/>
    < IMG风格=显示:无; ID =largeImageSRC =/>
  < /身体GT;
< / HTML>


解决方案

这两个你的 capturePhoto() capturePhotoEdit()功能需要有 destinationType 更新。

  navigator.camera.getPicture(
    onPhotoDataSuccess,
    onFail,
    {
        品质:50,
        destinationType.DATA_URL
    }
);

应该是这样的,

  navigator.camera.getPicture(
    onPhotoDataSuccess,
    onFail,
    {
        品质:50,
        destinationType:destinationType.DATA_URL
    }
);

I want to capture an image by using phonegap on Android phone. I try the code posted on Phonegap page but the camera does not appear. Any help is appreciated.Thank you very much.

It is the display on my phone

<!DOCTYPE html>
<html>
  <head>
    <title>Capture Photo</title>

    <script type="text/javascript" charset="utf-8" src="cordova-1.6.0.js"></script>
    <script type="text/javascript" charset="utf-8">

    var pictureSource;   // picture source
    var destinationType; // sets the format of returned value

    // Wait for Cordova to connect with the device
    //
    document.addEventListener("deviceready",onDeviceReady,false);

    // Cordova is ready to be used!
    //
    function onDeviceReady() {
        pictureSource=navigator.camera.PictureSourceType;
        destinationType=navigator.camera.DestinationType;
    }

    // Called when a photo is successfully retrieved
    //
    function onPhotoDataSuccess(imageData) {
      // Uncomment to view the base64 encoded image data
      // console.log(imageData);

      // Get image handle
      //
      var smallImage = document.getElementById('smallImage');

      // Unhide image elements
      //
      smallImage.style.display = 'block';

      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //
      smallImage.src = "data:image/jpeg;base64," + imageData;
    }

    // Called when a photo is successfully retrieved
    //
    function onPhotoURISuccess(imageURI) {
      // Uncomment to view the image file URI
      // console.log(imageURI);

      // Get image handle
      //
      var largeImage = document.getElementById('largeImage');

      // Unhide image elements
      //
      largeImage.style.display = 'block';

      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //
      largeImage.src = imageURI;
    }

    // A button will call this function
    //
    function capturePhoto() {
      // Take picture using device camera and retrieve image as base64-encoded string
      navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
        destinationType.DATA_URL });
    }

    // A button will call this function
    //
    function capturePhotoEdit() {
      // Take picture using device camera, allow edit, and retrieve image as base64-encoded string
      navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
        destinationType.DATA_URL });
    }

    // A button will call this function
    //
    function getPhoto(source) {
      // Retrieve image file location from specified source
      navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
        destinationType: destinationType.FILE_URI,
        sourceType: source });
    }

    // Called if something bad happens.
    //
    function onFail(message) {
      alert('Failed because: ' + message);
    }

    </script>
  </head>
  <body>
    <button onclick="capturePhoto();">Capture Photo</button> <br>
    <button onclick="capturePhotoEdit();">Capture Editable Photo</button> <br>
    <button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button><br>
    <button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button><br>
    <img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
    <img style="display:none;" id="largeImage" src="" />
  </body>
</html>
解决方案

Both your capturePhoto() and capturePhotoEdit() functions need to have the destinationType updated.

navigator.camera.getPicture(
    onPhotoDataSuccess,
    onFail,
    {
        quality: 50,
        destinationType.DATA_URL
    }
);

should be like this,

navigator.camera.getPicture(
    onPhotoDataSuccess,
    onFail,
    {
        quality: 50,
        destinationType: destinationType.DATA_URL
    }
);

这篇关于如何使用PhoneGap的显示Android手机上摄像头的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

1403页,肝出来的..

09-06 07:06