问题描述
我需要找到第二点的坐标。我知道弧度点之间的角度，我也知道向量的长度。
I need to find the coordinates of the second point. I know the angle between the points in radians and I also know the length of the vector.
我会真的很感激，如果有人能指出我的解决方案。
I would really appreciate if someone could point me towards the solution.
推荐答案
鉴于 L 作为向量的长度， Ang 角度
Given L as the length of the vector and Ang the angle
x2 = x1 + Math.cos(Ang) * L
y2 = y1 + Math.sin(Ang) * L
糟糕...我刚刚注意到Y轴从上到下的方向...
Konstantin Levin，你需要稍微调整一下，因为上面的公式假设一个典型的三角坐标系统。在您的情况下，公式应为：
Oops... I just noted the top to bottom orientation of the Y axis...Konstantin Levin, you will need adapt slightly because the formulas above assume a typical trigonometric coordinates system. In your case the formulas should be:
x2 = x1 + Math.cos(Ang) * L // unchanged
y2 = y1 - Math.sin(Ang) * L // minus on the Sin
此外（不言而喻，其中一个也说它......）参考角度应该是这样当y2 == y1和x2> x1时，Ang应该为零，并且当第二个点逆时针移动时它应该增加围绕第一个。
Also (what goes without saying, also goes in one says it...) the reference angle should be such that when y2 == y1 and x2 > x1, Ang should be zero, and it should increase as the second point is moved counter-clockwise around the first one.
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