二维数组按或列出 | 二维数组按或列出

本文介绍了二维数组按或列出的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

亲爱的，

我有以下二维数组：

Dear all,

I have the following Two Dimensional Array:

object[,] cellValues

[1,1 ] =x

[1,2] =y

[1,3] =z

[2,1] =a

[2,2] =b

[2,3] =c

[3,1] =我

[3,2] =j

[3 ，3] =k

[4,1] =p

[4,2] =q

[4,3] =r

[5,1] =m

[ 5,2] =n

[5,3] =o

现在我想改造上面的两个字典或列表中的维数：

1 [x，y，z]

2 [a，b，c]

3 [i，j，k]

4 [p，q，r]

5 [m，n，o]

如何使用LINQ和/ foreach这样做需要很长时间才能完成此操作？

请注意，Two Dimensional数组包含513360个值。

我尝试了什么：

[1,1] = "x"
[1,2] = "y"
[1,3] = "z"

[2,1] = "a"
[2,2] = "b"
[2,3] = "c"

[3,1] = "i"
[3,2] = "j"
[3,3] = "k"

[4,1] = "p"
[4,2] = "q"
[4,3] = "r"

[5,1] = "m"
[5,2] = "n"
[5,3] = "o"

Now I am trying to transform the above Two Dimensional array into Dictionary or List:

1 [x,y,z]
2 [a,b,c]
3 [i,j,k]
4 [p,q,r]
5 [m,n,o]

How to do this using LINQ as for/foreach is taking long time to complete this?
Please note that, the Two Dimensional array containf 513360 values.

What I have tried:

var xLimit = Enumerable.Range(0, cellValues.GetUpperBound(0) + 1);
var yLimit = Enumerable.Range(0, cellValues.GetUpperBound(1) + 1);
var result = xLimit.SelectMany(x => yLimit.Select(y => cellValues[x, y]));

推荐答案

var xLimit = Enumerable.Range(0, cellValues.GetUpperBound(0) + 1);
var yLimit = Enumerable.Range(0, cellValues.GetUpperBound(1) + 1);
var result = xLimit.AsParallel().SelectMany(x => yLimit.AsParallel().Select(y => cellValues[x, y]));

了解更多详情; []

public class Model
{
    public List<string> Values { get; set; }
}

string[,] parts = new string[,] {{"a","b","c"},{"d","e","f"}};
List<Model> list = new List<Model>();

//find out how big our array is
int dim1 = parts.GetLength(0);
int dim2 = parts.GetLength(1);

for (int i = 0; i < dim1; i++)
{
    List<string> values = new List<string>();
    for (int j = 0; j < dim2; j++)
    {
        values.Add(parts[i,j]);
    }
    list.Add(new Model(){ Values = values });
}

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