问题描述
我正在处理大量小文件,并使用combineFileInputFormat来避免执行大量映射任务。它工作正常,但问题是,我需要有每个文件的ID,这样所有的文件的ID是1.我怎么能保持文件的ID?我必须添加一些代码到我的combineFileInputFormat? / p>
配置当前正在处理的文件的配置属性,所以你应该能够从 map.input.file 属性获取当前文件名:
@Override
protected void map(Longwritable key,Text value,Context context){
String filePath = context.getConfiguration()。get(map.input.file );
如果你使用旧的API(mapred),属性名称是相同。I am working with large number of small files and have used combineFileInputFormat to avoid having a lot of map tasks. it is working properly but the problem is that i need to have the id of each file, in this way all of file's id is 1. how can i keep the ids of files?do i have to add some code to my combineFileInputFormat?
解决方案The CombineFileRecordReader configures a configuration property for the current file it is processing, so you should be able to obtain the current file name from the map.input.file property:
@Override protected void map(Longwritable key, Text value, Context context) { String filePath = context.getConfiguration().get("map.input.file"); }If you're using the old API (mapred), the property name is the same.
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