hdu 4176

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Class Statistics

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 233    Accepted Submission(s): 153

Problem Description
The
new principal of Woop Woop Public plans to meet the teaching team to
discuss the performance of the classes/teachers and, being a bean
counting fundamentalist, he wants to arm himself with some statistics
for the meetings.
Your task is to write a program that reads the
pupils' marks in each class and generates performance reports for the
principal prior to the meetings.
 
Input
The
input starts with an integer K (1 <= K <= 100) indicating the
number of classes on a line by itself. Each of the following K lines
gives a class's data, which starts with an integer N (2 <= N <=
50) indicating the number of pupils in the class. The number of pupils
is followed by their marks, given as integers, in the range of zero to
one hundred, separated by single spaces.
 
Output
The report for each class consists of two lines.
The first line consists of the sentence: "Class X", where X indicates the class number starting with the value of one.
The
second line reports the maximum class mark, minimum class mark and the
largest difference between consecutive marks (when sorted in
non-decreasing order) in the class using the formats shown in the sample
below.
 
Sample Input
2
5 30 25 76 23 78
6 25 50 70 99 70 90
 
Sample Output
Class 1
Max 78, Min 23, Largest gap 46
Class 2
Max 99, Min 25, Largest gap 25
 
Source
 
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#include<stdio.h>
#include<string.h>
#include<math.h>
#include<iostream>
#include<algorithm>
using namespace std;
int a[];
int main(){
int t;
scanf("%d",&t);
int cnt=;
while(t--){
int n;
cnt++;
memset(a,,sizeof(a));
scanf("%d",&n);
int temp=-,temp1;
for(int i=;i<n;i++){
scanf("%d",&a[i]); }
sort(a,a+n);
for(int i=;i<n;i++){ temp1=a[i]-a[i-];
if(temp1>temp)
temp=temp1;
}
printf("Class %d\n",cnt);
printf("Max %d, Min %d, Largest gap %d\n",a[n-],a[],temp); } return ;
}
05-22 14:20
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