1. 打开图片文件并转换为BitmapImage类
首先要做的自然是打开一个图片文件了,可以使用FileOpenPicker来手动选择图片,总之能拿到一个StorageFile都行。
//打开图片选择器,选择要发送的图片
var openPicker = new FileOpenPicker
{
ViewMode = PickerViewMode.Thumbnail,
SuggestedStartLocation = PickerLocationId.PicturesLibrary
};
openPicker.FileTypeFilter.Add(".jpg");
openPicker.FileTypeFilter.Add(".jpeg");
var file = await openPicker.PickSingleFileAsync();
也可以使用StorageFile.GetFileFromApplicationUriAsync获取,下面代码得到的文件是应用独立存储文件夹LocalState里的1.jpg文件。
var path = "ms-appdata:///local/1.jpg";
var file = await StorageFile.GetFileFromApplicationUriAsync(new Uri(path));
接下来将文件打开,并把文件流写入到BitmapImage中。
//将图片文件读取为BitmapImage
var fileStream = await file.OpenReadAsync();
var bitmap = new BitmapImage();
await bitmap.SetSourceAsync(fileStream);
2. 将图片byte[]信息转换为bitmap
首先要把byte[]转换为IRandomAccessStream然后再使用BitmapImage.SetSourceAsync方法将流写入bitmap中,单纯的MemoryStream是不能直接写入到bitmap中的。
public async static Task<BitmapImage> ConvertBytesToBitmapImage(byte[] bytes)
{
try
{
if (bytes == null || bytes.Length == ) return null; var stream = new MemoryStream(bytes);
var randomAccessStream = new InMemoryRandomAccessStream();
using (var outputStream = randomAccessStream.GetOutputStreamAt())
{
var dw = new DataWriter(outputStream);
var task = new Task(() => dw.WriteBytes(stream.ToArray()));
task.Start();
await task;
await dw.StoreAsync();
await outputStream.FlushAsync(); var bitmapImage = new BitmapImage();
await bitmapImage.SetSourceAsync(iRandomAccessStream);
return bitmapImage;
}
}
catch (Exception exception)
{
Debug.WriteLine("[Error] Convert bytes to BitmapImage failed,exception:{0}", exception);
return null;
}
}