问题描述
我必须读取包含字符串列表的文件。我正在尝试按照 会是我的问题，除了OP完全被劝阻使用文件。如果我想使用Apache方法，我需要一个文件，这是我最初解决问题的首选方法。
This post would be my question, except the OP was dissuaded from using files entirely. I need a file if I want to use the Apache method, which is the my preferred solution to my initial problem.
我的文件很小（一百行左右）每个程序实例都有一个单例，所以我不必担心在内存中有另一个文件副本。因此我可以使用更基本的方法来读取文件，但到目前为止看起来像 FileUtils.readLines 可能更清晰。我如何从资源到文件。
My file is small (a hundred lines or so) and a singleton per program instance, so I do not need to worry about having another copy of the file in memory. Therefore I could use more basic methods to read the file, but so far it looks like FileUtils.readLines could be much cleaner. How do I go from resource to file.
推荐答案
Apache Commons-IO有一个以及FileUtils，其中包含类似于FileUtils中的方法。
Apache Commons-IO has an IOUtils class as well as a FileUtils, which includes a readLines method similar to the one in FileUtils.
所以你可以使用或并将结果传递给 IOUtils.readLines 以获取列表< String> 您文件的内容：
So you can use getResourceAsStream or getSystemResourceAsStream and pass the result of that to IOUtils.readLines to get a List<String> of the contents of your file:
List<String> myLines = IOUtils.readLines(ClassLoader.getSystemResourceAsStream("my_data_file.txt"));
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