数组被php中的最后一个元素覆盖

问题描述

存储在 $ g 中的结果是1和2.下面编写的以下代码，即我的 $ array ['music'] 仅存储最后一个元素那是2.但是我想要在foreach下执行2次sql查询，并将 $ g 的值与 mu_id (mu_id 是另一个表 music 中的列名，并将第1行和第2行的所有行数据存储到 $ array ['music'] 中.

The result stored in $g is 1 and 2. The following code I've written below, my $array['music'] stores only the last element that is 2. But what I want is to execute my sql query 2 times under foreach and match the value of $g which is 1 and 2 with mu_id (mu_id is the column name from another table music) and store all the rows data of row 1 and 2 in to $array['music'].

它仅存储第二行(2)而不存储1，或者在第二次执行内部循环时覆盖它.如果有任何逻辑可以使其正常工作，请告诉我.

It is storing only for the second row (2) not for 1 or it is overwriting it when it is executing for the second time inside loop. If there is any logic to make it work then please let me know.

    foreach($genre as $g)
    {
        echo $g;
        echo "<br>";
        $array['music'] = $m -> where('mu_id', $g ) -> get();
    }

推荐答案

您每次都在重新声明整个数组，而不是添加整个数组，而是使用以下声明:

You're redeclaring the entire array each time rather than adding to it, use this instead:

foreach($genre as $g)
{
    $array['music'][] = $m->where('mu_id', $g)->get();
}

甚至更好，更少的查询:

Or even better, less queries:

$array['music'] = $m->where_in('mu_id', $genre)->get();

这篇关于数组被php中的最后一个元素覆盖的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！