问题描述
如何做整数 - >字符串转换已经在互联网上多次回答...但是，我正在寻找最紧凑的C ++ - 方式这样做。
How to do integer -> string conversion has been answered many times on the internet... however, I'm looking for the most compact "C++-way" to do this.
因为你能够使用重载的+运算符连接字符串，所以最好能够沿着python-ish的行做一些事情
x =（stringVariable + str（intVariable） ）连接，但我不知道如果有一个规范的方式来做这个在C + +。
Since you're able to concatenate strings using the overloaded + operator, it would be preferable to be able to do something along the lines of the python-ishx = (stringVariable + str(intVariable)) concatenation, but I don't know if there's a canonical way to do this in C++.
我看到的最常见的解决方案是：
The most common solutions I see are:
stringstream：如果可能的话， 3行代码（声明，写入流，转换为字符串）只是为了连接一些字母和数字。
stringstream: If possible, it would be nice not to have 3 lines of code (declaration, writing to the stream, conversion to string) just to concatenate some letters and numbers.
itoa：一个规范的C ++解决方案。此外，我认为itoa在技术上是非标准的，虽然我可能是错误的。
itoa: this works, but I'm looking for a canonical C++ solution. Also, I think itoa is technically non-standard although I could be wrong.
boost格式/ boost词法铸造：这也工作，但在香草C ++
boost format / boost lexical cast: this works too, but is there nothing in vanilla C++ that does the job?
推荐答案
#include <string>
字符串到整数： int n = std :: stoi（s）
整数到字符串： std :: string s = std :: to_string（n）;
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