报告出现时如何启用datagridcell？

问题描述

Hi how can i a Button column to a Datagrid programatically. I want to do this through code in codebehind file.<pre>if the status shows "REPORTED" then enable the datagridbutton in wpf</pre>

int rowIndex = 10;
var rowData = dataGrid1.Items[rowIndex] as DataRowView;
rowData["LinkRPT"] = "";
dataGrid1.Columns[10].Visibility = Visibility.Visible;
SqlConnection con = new SqlConnection("Data Source=WINCTRL-TNT3FMR\\SQLEXPRESS;Initial
            Catalog=Roamani;Integrated Security=True");
if (dataGrid1.SelectedItems.Count > 0)
{
    for (int i = 0; i < dataGrid1.SelectedItems.Count; i++)
    {
        System.Data.DataRowView selectedFile= (System.Data.DataRowView)dataGrid1.SelectedItem;//Row is detected and stored in selectedfile object
        string str = Convert.ToString(selectedFile.Row.ItemArray[10]);
        string sts = Convert.ToString(selectedFile.Row.ItemArray[9]);

        string query = "SELECT Report FROM StudyTable WHERE StudyUID='" + str + "' AND status='3'";
        SqlCommand cmd = new SqlCommand(query, con);
        con.Open();
        SqlDataReader rdr = cmd.ExecuteReader();
        try
        {
            while (rdr.Read())
            {
                query = rdr.GetString(0);
                //dataGrid1.Columns[10] = query;
                OpenReport(query);
            }
        }
        catch (Exception ex)
        {
            ReallySimpleLog.ReallySimpleLog.WriteLog(ex);
        }
    }
}
con.Close();

推荐答案

<DataTemplate x:Key="columnTemplate">
      <Button x:Uid="rowButton" Content="Do some thing" Margin="2" IsEnabled="{Binding IsActive}"/>
</DataTemplate>

在服务器端做一些这样的事情：

In server side do some thing like this :

private void FillDate()
{
      ObservableCollection<mydate> data = new ObservableCollection<mydate>();
      for (int i = 1; i <= 20; i++)
          data.Add(new MyDate()
          {
                ID = i,
                Name = "Name" + i,
                Family = "Family" + i,
                IsActive = true
          });

      dataGrid.ItemsSource = data;

      DataGridTemplateColumn tColumn = new DataGridTemplateColumn();
      tColumn.CellTemplate = (DataTemplate)this.FindResource("columnTemplate");
      tColumn.Header = "Button column";
      dataGrid.Columns.Add(tColumn);
}

...

...

public class MyDate : INotifyPropertyChanged
    {
        public MyDate() { }

        private int _iD;
        public int ID
        {
            get { return _iD; }
            set
            {
                _iD = value;
                Notify("ID");
            }
        }

        private string _name = "";
        public string Name
        {
            get
            {
                return _name;
            }
            set
            {
                _name = value;
                Notify("Name");
            }
        }

        private string _family = "";
        public string Family
        {
            get
            {
                return _family;
            }
            set
            {
                _family = value;
                Notify("Family");
            }
        }

        private bool _isActive = false;
        public bool IsActive
        {
            get { return _isActive; }
            set
            {
                _isActive = value;
                Notify("IsActive");
            }
        }

        public event PropertyChangedEventHandler PropertyChanged;
        private void Notify(string property)
        {
            if (PropertyChanged != null)
                PropertyChanged(this, new PropertyChangedEventArgs(property));
        }
    }

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