c尖锐的字符串连接

问题描述

我有两个字符串Rahul，Mishra我想显示像

frist字母的第一个字母然后第一个字符串的第一个字母... 。



前RAHUL

MISHRA



输出：

RMAIHSUHLRA

i have two strings "Rahul" ,"Mishra" i want to show like
frist letter of frist string then first letter of second string ...then 2 letter of first string ....

ex-RAHUL
MISHRA

output:
RMAIHSUHLRA

推荐答案

using System.Linq;

static void Main(string[] args)
{
    string mixed = Interleave("RAHUL", "MISHRA");
}

public static string Interleave(string s1, string s2)
{
    StringBuilder sb = new StringBuilder();
    s1.Zip(s2, (c1, c2) => sb.Append(c1).Append(c2)).Count();   // .Count() to force the Lazy evaluation!
    if (s1.Length > s2.Length)
    {
        sb.Append(s1.Substring(s2.Length));
    }
    else if (s2.Length > s1.Length)
    {
        sb.Append(s2.Substring(s1.Length));
    }
    return sb.ToString();
}

public static string GetString(string string1,string string2)
      {
          char[] str1 = string1.ToCharArray();
          char[] str2 = string2.ToCharArray();

          string finalString = "";
          int length = str1.Length > str2.Length ? str2.Length : str1.Length;
          for (int i = 0; i < length ; i++)
          {
              finalString = finalString + str1[i] + str2[i];
          }
          if (str1.Length > str2.Length)
          {
              int difference = str1.Length - str2.Length;
              for (int i = 0; i < difference; i++)
              {
                  char rem = str1[str2.Length + i];
                  finalString = finalString + rem;
              }

          }
          else
          {
              int difference = str2.Length - str1.Length;
              for (int i = 0; i < difference; i++)
              {
                  char rem = str2[str1.Length + i];
                  finalString = finalString + rem;
              }
          }
          return finalString;
      }

如下所示传递你的字符串

Pass your string like below

string finalString = GetString("RAHUL", "MISHRA");

希望这有帮助

Hope this helps

这篇关于c尖锐的字符串连接的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！