查找字符串中数组值的首次出现

问题描述

我有一个值数组，所有值都包含一个单词，我希望能够找到首先在字符串中找到的那些值。

I've got an array of values, all containing one word, and I'd like to be able to find which of those values is found first in a string.

$materials = array("cotton","silk","polyester","denim","wool");
$string1 = "The fabric composition of this jacket is 100% cotton (body) and 65% polyester / 35% cotton (lining)";
$string2 = "The jeans are made from denim with cotton pockets";

因此，对于$ string1，我想说它首先找到棉作为材质和$ string2，我想说它首先找到了牛仔布。

So for the $string1, I'd like it to say that it found 'cotton' first as the material and for the $string2 I'd like it to say that it found 'denim' first.

您知道这样做的方法吗？我本来是在查看foreach循环的，但它会按数组的顺序排列，这意味着它将同时为这两个字符串带来棉布，因为这是数组中的第一个：

Do you know a way of doing this? I was originally looking at a foreach loop but it would go in order of the array meaning it would also bring 'cotton' back for both strings as that's the first one in the array:

foreach ($materials as $material) {
    if (stripos($string1, $material) !== FALSE) {
        $product_material1 = $material;
        break;
    }
}

推荐答案

$materials = array("cotton","silk","polyester","denim","wool");
$string1 = "The fabric composition of this jacket is 100% cotton (body) and 65% polyester / 35% cotton (lining)";
$string2 = "The jeans are made from denim with cotton pockets";

$firstMatch = array_shift(array_intersect(str_word_count($string1, 1), $materials));
var_dump($firstMatch);

$firstMatch = array_shift(array_intersect(str_word_count($string2, 1), $materials));
var_dump($firstMatch);

如果没有匹配项，您将得到 null

If there's no match, you'll get a null

请注意，它区分大小写

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