我如何获得一个PHP类构造函数来调用其父代的父代构造函数? | 我如何获得一个PHP类构造函数来调用其父代的父代构造函数

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问题描述

我需要在PHP中使用一个类构造函数来调用其父级的父级(祖父母?)构造函数，而不调用父级构造函数.

I need to have a class constructor in PHP call its parent's parent's (grandparent?) constructor without calling the parent constructor.

// main class that everything inherits
class Grandpa
{
    public function __construct()
    {

    }

}

class Papa extends Grandpa
{
    public function __construct()
    {
        // call Grandpa's constructor
        parent::__construct();
    }
}

class Kiddo extends Papa
{
    public function __construct()
    {
        // THIS IS WHERE I NEED TO CALL GRANDPA'S
        // CONSTRUCTOR AND NOT PAPA'S
    }
}

我知道这是一件奇怪的事情，我正试图找到一种闻起来并不难闻的方法，但是我很想知道是否有可能.

I know this is a bizarre thing to do and I'm attempting to find a means that doesn't smell bad but nonetheless, I'm curious if it's possible.

推荐答案

丑陋的解决方法是将布尔参数传递给Papa，指示您不希望解析其构造函数中包含的代码.即:

The ugly workaround would be to pass a boolean param to Papa indicating that you do not wish to parse the code contained in it's constructor. i.e:

// main class that everything inherits
class Grandpa
{
    public function __construct()
    {

    }

}

class Papa extends Grandpa
{
    public function __construct($bypass = false)
    {
        // only perform actions inside if not bypassing
        if (!$bypass) {

        }
        // call Grandpa's constructor
        parent::__construct();
    }
}

class Kiddo extends Papa
{
    public function __construct()
    {
        $bypassPapa = true;
        parent::__construct($bypassPapa);
    }
}

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