问题描述
C ++中的一些功能是类型安全的，而其他一些功能则不是。
There are some features in C++ that are type safe and some other features that are not.
C ++类型安全性示例：
Example of C++ type safety:
char c = 'a';
int *p = &c; // this is not allowed (compiler error)
C ++缺少类型安全性的示例：
Example of C++ lack of type safety:
int *p; // I don't have to initialize p, and so it will have some junk/random value
*p = 12345; // this will probably lead to segmentation fault!
我读了几篇文章说C ++不是类型安全的语言。我可以认为它是一个非类型安全的语言，或者更准确地说它是一个部分类型安全的语言？
I have read in a couple of articles that C++ is not a type safe language. Can I consider it to be a non type safe language, or is it more accurate to say that it is a partially type safe language?
推荐答案
这是合理和几乎有意义说C ++是一种部分类型安全的语言。
It's reasonable and practically meaningful to say that C++ is a partially type safe language.
作为原始中期到1970年代末C的扩展，它被设计为一种高级便携式汇编语言，使Unix更便携，更易于维护。 C ++为其新功能添加了类型安全性，但目标是主要与C兼容（特别是使用所有现有的C库，包括其头文件），C的原始核心必须保留原样。
C++ started as an extension of original mid- to late 1970's C, which was designed as a kind of high level portable assembly language, to make Unix more portable and easier to maintain. C++ added type safety for its new features, but with the goal of being mainly compatible with C (in particular using all those existing C libraries, including their headers) the original core of C had to be left as it was.
特别是，C ++得到了数组到C指针的衰减。在C ++中，它不是类型安全的，因为它允许从 Derived 指向 Base 的指针，它可以依次被索引但具有未定义的行为。
In particular, C++ got the decay of array to pointer from C. In C++ it isn't type safe because it allows an implicit conversion from array of Derived to pointer to Base, which can in turn be indexed but with Undefined Behavior.
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