R:标题用par()减半

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问题描述

我有这个数字:

require(corrplot)
par(oma=c(0,0,2,0), mfrow = c(1, 3))
for (country in c("Italy","Germany","Afghanistan")) {
  corrplot.mixed(cor(data.frame(v1=rnorm(40),
                                v2=rnorm(40),
                                v3=rnorm(40),
                                v4=rnorm(40),
                                v5=rnorm(40),
                                v6=rnorm(40),
                                v7=rnorm(40),
                                v8=rnorm(40)), use="pairwise.complete.obs"),
                 main=country)
}
par(mfrow = c(1, 1))

产生的标题减少一半:

按照此答案，我设置了oma=c(0,0,2,0)，但它不会影响结果.我不确定应该修改哪个边距.我查看了?par并修改了"oma"，"omd"，"omi"，"mai"，"mar"，但没有结果.

Following this answer I set oma=c(0,0,2,0) but it does't affect the results. I am not sure which margin I should modify. I looked at ?par and modified "oma", "omd", "omi", "mai", "mar" with no result.

推荐答案

我发现将mar参数传递给corrplot是有效的:

I found that passing mar arguments to corrplot was effective:

    png(height=300,width=600);par(oma=c(0,0,2,0), mfrow = c(1, 3))
for (country in c("Italy","Germany","Afghanistan")) {
  corrplot.mixed(cor(data.frame(v1=rnorm(40),
                                v2=rnorm(40),
                                v3=rnorm(40),
                                v4=rnorm(40),
                                v5=rnorm(40),
                                v6=rnorm(40),
                                v7=rnorm(40),
                                v8=rnorm(40)), use="pairwise.complete.obs"),
                 main=country, mar=c(0,0,2,0))
};dev.off()

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