六边形中不同颜色的线条

问题描述

我只是想知道如何在六边形的每一行上获得不同的颜色.下面我有所需的输出和输入.

立即输出 -

为了更接近目标图像，您需要将六边形(圆形)的各个部分绘制为梯形.

导入海龟从 itertools 导入循环颜色 = [#9c2921"、#f5d905"、#cf8e04"、]NUM_SIDES = 6SIDE_LENGTH = 50笔宽 = 30圆周半径 = SIDE_LENGTH海龟.width(1)turtle.speed('fastest') # 因为我没有耐心颜色 = 周期(颜色)对于范围内的 _(4):乌龟.penup()海龟.sety(-circumradius)乌龟.pendown()对于 _ 范围内(NUM_SIDES):龟.颜色(下一个(颜色))龟.circle(圆周半径，范围= 360/NUM_SIDES，步骤= 1)乌龟.right(90)海龟.begin_fill()乌龟.转发(PEN_WIDTH/2)乌龟.right(120)龟.forward(圆周半径 + PEN_WIDTH/2)乌龟.right(120)乌龟.转发(PEN_WIDTH/2)海龟.end_fill()海龟.begin_fill()乌龟.转发(PEN_WIDTH/2)乌龟.right(60)龟.forward(圆周半径 - PEN_WIDTH/2)乌龟.right(60)乌龟.转发(PEN_WIDTH/2)海龟.end_fill()龟.left(90)圆周半径 += PEN_WIDTH*2海龟.hideturtle()乌龟.完成()

I was just wondering on how to get different colors on each line of the hexagon. Below I have the desired output and input.

Output Right Now - Link to output right now

Output I want - Link to output I want

import turtle as trtl

colors = ["#9c2921", "#cf8e04","#f5d905",]

#--------------------
num_sides = int(input("Enter the number of sides(Enter 6 to get the output of the real image): "))

if num_sides == 6:
  print("Desired artwork is displayed")

side_length = 25
circumradius = side_length


angle = 360/len(colors)
trtl.width(10)



for color in colors:
    trtl.color(color)
    trtl.pensize(10)
    for move_turtle in range(1):
      trtl.penup()
      trtl.sety(-circumradius)
      trtl.pendown()
      trtl.circle(circumradius, steps = num_sides)

      circumradius *= 2

trtl.hideturtle()

解决方案

Oddly, your program looks like code I wrote in response to your previous question that has neither been accepted nor upvoted. Moving on:

Given this circle() and a fat pen based approach for drawing the hexagons, I believe this is about the best you can do:

import turtle
from itertools import cycle

COLORS = ["#9c2921", "#f5d905", "#cf8e04",]
NUM_SIDES = 6
SIDE_LENGTH = 50
PEN_WIDTH = 25

circumradius = SIDE_LENGTH

turtle.width(PEN_WIDTH)

color = cycle(COLORS)

for _ in range(4):

    turtle.penup()
    turtle.sety(-circumradius)
    turtle.pendown()

    for _ in range(NUM_SIDES):
        turtle.color(next(color))
        turtle.circle(circumradius, extent=360/NUM_SIDES, steps=1)

    circumradius += PEN_WIDTH*2

turtle.hideturtle()
turtle.done()

To get closer to the target image, you'd need to draw the individual segments of the hexagon (circle) as trapezoids.

import turtle
from itertools import cycle

COLORS = ["#9c2921", "#f5d905", "#cf8e04",]
NUM_SIDES = 6
SIDE_LENGTH = 50
PEN_WIDTH = 30

circumradius = SIDE_LENGTH

turtle.width(1)
turtle.speed('fastest')  # because I have no patience

color = cycle(COLORS)

for _ in range(4):

    turtle.penup()
    turtle.sety(-circumradius)
    turtle.pendown()

    for _ in range(NUM_SIDES):
        turtle.color(next(color))
        turtle.circle(circumradius, extent=360/NUM_SIDES, steps=1)
        turtle.right(90)

        turtle.begin_fill()
        turtle.forward(PEN_WIDTH/2)
        turtle.right(120)
        turtle.forward(circumradius + PEN_WIDTH/2)
        turtle.right(120)
        turtle.forward(PEN_WIDTH/2)
        turtle.end_fill()

        turtle.begin_fill()
        turtle.forward(PEN_WIDTH/2)
        turtle.right(60)
        turtle.forward(circumradius - PEN_WIDTH/2)
        turtle.right(60)
        turtle.forward(PEN_WIDTH/2)
        turtle.end_fill()

        turtle.left(90)

    circumradius += PEN_WIDTH*2

turtle.hideturtle()
turtle.done()

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