python中的复杂列表切片/索引

问题描述

我有一个看起来像这样的列表:

I have a list that looks like this:

lst = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]

我想生成一个过滤列表，如下所示:

I'd like to generate a filtered list that looks like this:

filtered_lst = [2, 6, 7, 9, 10, 13]

Python是否提供自定义切片的约定.诸如此类的东西:

Does Python provide a convention for custom slicing. Something such as:

lst[1, 5, 6, 8, 9, 12] # slice a list by index

推荐答案

使用 operator.itemgetter() :

from operator import itemgetter

itemgetter(1, 5, 6, 8, 9, 12)(lst)

演示:

>>> from operator import itemgetter
>>> lst = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
>>> itemgetter(1, 5, 6, 8, 9, 12)(lst)
(2, 6, 7, 9, 10, 13)

这将返回一个元组；如果需要的话，使用list(itemgetter(...)(lst))强制转换为列表.

This returns a tuple; cast to a list with list(itemgetter(...)(lst)) if a that is a requirement.

请注意，这等效于带有一组索引而不是范围的切片表达式(lst[start:stop])；不能用作左侧切片分配(lst[start:stop] = some_iterable).

Note that this is the equivalent of a slice expression (lst[start:stop]) with a set of indices instead of a range; it can not be used as a left-hand-side slice assignment (lst[start:stop] = some_iterable).

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