存储对`call`函数的引用

问题描述

我今天早些时候注意到了一些奇怪的事情。我似乎无法存储对函数的调用属性的引用，然后执行它。示例：

I noticed something curious earlier today. I can't seem to store a reference to the call property of a function, then execute it. Example:

var log = console.log;
log.call(console, 'This works');

var logCall = console.log.call;
logCall(console, 'This does not');

对我来说，这似乎是完全合法的Javascript，但第二次调用总是给我错误 undefined不是函数。随意使用它来，你会得到相同的结果。

To me, this seems like perfectly legal Javascript, but the second invocation always gives me the error that undefined is not a function. Feel free to play around with it here, you'll get the same results.

那么为什么Javascript会阻止我以这种方式调用调用？

So why does Javascript prevent me from calling call in this manner?

编辑：在阅读SimpleJ的回答后，我终于明白了。因此，我将更新以了解如何使上述工作：

I finally got it straight in my head after reading SimpleJ's answer. So I'm going to update this with how you can get the above to work:

var log = console.log;
log.call(console, 'This works');

var logCall = console.log.call;
logCall.call(console.log, console, 'This works now too');

问题是 console.log 是收到正确的此值，但 console.log.call 未获得正确的这个值。所以你可以看到，我基本上必须执行 console.log.call.call 。显然你从来没有真正使用这样的代码，我只是很好奇。

The problem was that console.log was receiving the proper this value, but console.log.call wasn't given a proper this value. So as you can see, I basically had to execute console.log.call.call. Obviously you'd never really use code like this, I was just curious.

推荐答案

你需要保持绑定到控制台。试试这个：

You need to keep the binding to console. Try this:

var logCall = console.log.call.bind(console.log);
// example: logCall(console, "foobar");

或

var log = console.log.bind(console);
// example: log("foobar");

对于 log 的绑定引用。

编辑：
jsfiddle：

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