问题描述
我想添加一个功能,用户可以在其中转到下一个搜索结果.谢谢,@ggorlen 帮助进行递归搜索.
I would like to add a function in which users can go to the next searched result. Thanks, @ggorlen for helping with the recursive search.
我有一个递归搜索函数,它给出第一个值并使它们 selected = true,如果它在嵌套数组中,则使 showTree=true.
I have a recursive search function that gives the first value and makes them selected = true and if it is in nested array make showTree=true.
如何添加一个函数,如果用户单击下一个搜索记录,则 selected: true 将设置为下一个结果并删除前一个结果?
How I can add a function in which if the user clicks the next search record then the selected: true will set to the next result and remove the previous one?
并且基于新的结果 showTree 会改变.
and based on the new results showTree will change.
如何添加一个根据搜索次数更新的变量...
How to add a variable which gets updated based on the number of time search is called...
上一条记录选项,方便用户返回上一条结果
previous record option so user can go back to the previous result
const expandPath = (nodes, targetLabel) => {
for (const node of nodes) {
if (node.label.includes(targetLabel)) {
return (node.selected = true);
} else if (expandPath(node.item, targetLabel)) {
return (node.showTree = true);
}
}
};
// Output
expandPath(testData, 'ch');
//// add variable for count example: 1 of 25
console.log(testData);
//if user click on nextrecord after search
//nextrecord(){
//logic to remove the selected true from current and add for next
//update showtree
//update recordNumber of totalValue example: 2 of 25
//}
//child3 should get selected true and remove child1 selected true and showtree
//same add showTree= true based on selected value
//if user click on previous record after search
//previousrecord(){
//logic to remove the selected true from current and add for previous
//update showtree
//update recordNumber of totalValue example: 1 of 25
//}
console.log(testData);
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script>
// Test Data
const testData = [
{
id: 1,
label: 'parent1',
item: [
{
id: 21,
label: 'child1',
item: [
{
id: 211,
label: 'child31',
item: [
{
id: 2111,
label: 'child2211',
item: [{ id: 21111, label: 'child22111' }]
}
]
},
{ id: 222, label: 'child32' }
]
},
{
id: 22,
label: 'child2',
item: [
{
id: 221,
label: 'child421',
item: [{ id: 2211, label: 'child2211' }]
},
{ id: 222, label: 'child222' }
]
}
]
},
{
id: 2,
label: 'parent2',
item: [
{
id: 21,
label: 'child2',
item: [
{
id: 511,
label: 'child51',
item: [
{
id: 5111,
label: 'child5211',
item: [{ id: 51111, label: 'child52111' }]
}
]
},
{ id: 522, label: 'child352' }
]
}
]
}
];
</script>
推荐答案
可以参考下面的代码
const testData = [
{
id: 1,
label: 'parent1',
item: [
{
id: 21,
label: 'child1',
item: [
{
id: 211,
label: 'child31',
item: [
{
id: 2111,
label: 'child2211',
item: [{ id: 21111, label: 'child22111' }]
}
]
},
{ id: 222, label: 'child32' }
]
},
{
id: 22,
label: 'child2',
item: [
{
id: 221,
label: 'child421',
item: [{ id: 2211, label: 'child2211' }]
},
{ id: 222, label: 'child222' }
]
}
]
},
{
id: 2,
label: 'parent2',
item: [
{
id: 21,
label: 'child2',
item: [
{
id: 511,
label: 'child51',
item: [
{
id: 5111,
label: 'child5211',
item: [{ id: 51111, label: 'child52111' }]
}
]
},
{ id: 522, label: 'child352' }
]
}
]
}
];
// flatten down tree to array and add parent pointer
const flatten = (data) => {
let flattenData = [data]
if (data.item) {
for (const item of data.item) {
item.parent = data;
flattenData = flattenData.concat(flatten(item));
}
}
return flattenData;
}
let flattenData = [];
// flatten down the test data
for (const data of testData) {
flattenData = flattenData.concat(flatten(data));
}
// to update showTree flag
const toggle = (item, expand = true) => {
const parent = item.parent;
if (parent) {
parent.showTree = expand;
if (parent.parent) {
return toggle(parent, expand);
}
return parent;
}
return item;
}
/**
*
* @param {targetLabel} query
* @returns function navigate with param forward flag
*/
const seach = (query) => {
let index = -1;
const items = flattenData.filter(x => x.label.includes(query));
return (forward = true) => {
if (index > -1) {
items[index].selected = false;
toggle(items[index], false);
}
index = index + (forward ? 1 : -1);
let item = null;
if (index > -1 && index < items.length) {
items[index].selected = true;
item = toggle(items[index], true);
}
return {
item,
index,
length: items.length
}
}
}
const navigate = seach('child5211');
// next result
let result = navigate();
// previous result
result = navigate(false);
// result will look like this
/**
* {
* item: root of current item with showTree and selected falgs or null if out of bound,
* index: current match,
* length: total match
* }
*
*/
这篇关于更新搜索结果的计数并根据用户在对象数组中搜索的次数更改选择的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!