递归查找文件并根据其完整路径重命名

问题描述

我要搜索具有特定名称的文件，将该名称修改为完整路径，然后将结果复制到另一个文件夹.

I'm looking to search for files of a specific name, modify the name to the full path and then copy the results to another folder.

是否可以使用完整路径作为文件名来更新每个查找结果；即

Is it possible to update each find result with the full path as the file name; i.e.

./folder/subfolder/my-file.csv

成为

folder_subfolder_my-file.csv

我正在使用以下内容列出文件，并希望编写脚本.

I am listing the files using the following and would like to script it.

find . -name my-file.csv -exec ls {} \;

推荐答案

由于您正在使用bash，因此可以利用 globstar 并使用 for 循环:

Since you're using bash, you can take advantage of globstar and use a for loop:

shopt -s globstar # set globstar option
for csv in **/my-file.csv; do
  echo "$csv" "${csv//\//_}"
done

shopt -u globstar # unset the option if you don't want it any more

启用 globstar 后， ** 进行递归搜索(类似于 find 的基本功能).

With globstar enabled, ** does a recursive search (similar to the basic functionality of find).

"$ {csv//\//_}" 是 $ {var//match/replace} 的示例，它对所有 match (此处是转义的/)与 replace 的实例.

"${csv//\//_}" is an example of ${var//match/replace}, which does a global replacement of all instances of match (here an escaped /) with replace.

如果您对输出感到满意，则将 echo 更改为 mv .

If you're happy with the output, then change the echo to mv.

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