问题描述
代码：
#include <stdio.h>
#define NEWLINE '\n'
#define SPACE ' '
int main(void)
{
int ch;
int count = 0;
while((ch = getchar()) != EOF)
{
if(ch != NEWLINE && ch != SPACE)
count++;
}
printf("There are %d characters input\n" , count);
return 0;
}
问题：
-
一切正常，它将忽略空格和换行符，并将输入的字符数输出到屏幕上（在此程序中，我只使用逗号，感叹号，数字或任何可打印的特殊符号字符，例如&字符），当我点击EOF模拟时，它是
^ z。
但是当我在程序中输入这一行时出了点问题。例如，我输入以下内容： abcdefg ^ z ，这意味着我在 ^ z 。程序将继续要求输入，而不是终止程序并打印出总字符。
But there's something wrong when I input this line to the program. For example I input this: abcdefg^z, which means I input some character before and on the same line as ^z. Instead of terminating the program and print out total characters, the program would continue to ask for input.
仅当我指定<$时，EOF终止字符输入才有效c $ c> ^ z 或执行以下操作： ^ zabvcjdjsjsj 。为什么会发生这种情况？
The EOF terminating character input only works when I specify ^z on a single line or by doing this: ^zabvcjdjsjsj. Why is this happening?
推荐答案
几乎在每个终端驱动程序中都是如此。使用Linux，您会得到相同的行为。
This is true in almost every terminal driver. You'll get the same behavior using Linux.
您的程序直到 \n 或 ^ z才真正执行循环您已在行尾输入。终端驱动程序正在缓冲输入，直到发生输入才将其发送给您的进程。
Your program isn't actually executing the loop until \n or ^z has been entered by you at the end of a line. The terminal driver is buffering the input and it hasn't been sent to your process until that occurs.
在一行的末尾，按 ^ z （或在Linux上为 ^ d ）不会 导致终端驱动程序发送EOF。它只会使它刷新缓冲区到您的进程（没有 \n ）。
At the end of a line, hitting ^z (or ^d on Linux) does not cause the terminal driver to send EOF. It only makes it flush the buffer to your process (with no \n).
命中 ^ z （或Linux上的 ^ d ）在行首被终端解释为我想发信号给EOF。
Hitting ^z (or ^d on Linux) at the start of a line is interpreted by the terminal as "I want to signal EOF".
如果在循环中添加以下内容，则可以观察到此行为：
You can observe this behavior if you add the following inside your loop:
printf("%d\n",ch);
运行程序：
$ ./test
abc <- type "abc" and hit "enter"
97
98
99
10
abc97 <- type "abc" and hit "^z"
98
99
要更好地理解这一点，您必须意识到EOF不是字符。 ^ z 是用于终端本身的用户命令 。因为终端负责接收用户输入并将其传递给流程，所以这变得很棘手，从而造成混乱。
To better understand this, you have to realize that EOF is not a character. ^z is a user command for the terminal itself. Because the terminal is responsible for taking user input and passing it to processes, this gets tricky and thus the confusion.
一种查看方式是点击 ^ v 然后点击 ^ z 作为程序的输入。
A way to see this is by hitting ^v then hitting ^z as input to your program.
^ v 是另一个告诉终端的终端命令， 嘿，我要输入的下一个内容-不要将其解释为终端命令；而是将其传递给流程的输入。
^v is another terminal command that tells the terminal, "Hey, the next thing I type - don't interpret that as a terminal command; pass it to the process' input instead".
这篇关于Windows命令提示符中的EOF不会终止输入流的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！