将字符串集合连接成一个带分隔符和封闭字符的字符串

将字符串集合连接成一个带分隔符和封闭字符的字符串

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问题描述

我有一个希望链接成一个目标字符串的源字符串集合。

I have a collection of source strings that I wish to concatenate into one destination string.

源集合如下所示:

{ "a", "b", "c" }

我希望输出字符串为:

abc

但是有时候,我也想要分隔符。因此,对于相同的输入,现在的输出将是:

But sometimes, I want a separator as well. So for the same input, now the output is to be:

a-b-c

最后,有时有时需要用其他字符将输入括起来,在这种情况下, [] ,导致输出为:

And finally, the input sometimes needs to be enclosed in other characters, in this case [], causing the output to be:

[a]-[b]-[c]

一个空的源集合应该产生一个空字符串。我该怎么办?

An empty source collection should yield an empty string. How would I go about this?

推荐答案

您可以使用 。

You can do this using the static String.Join() method.

其基本用法如下:

string[] sourceData = new[] { "a", "b", "c" };
string separator = "";
var result = string.Join(separator, sourceData);

当您提供一个空的分隔符时,传递的值将简单地与此连接: abc

When you supply an empty separator, the passed values will simply be concatenated to this: "abc".

要使用特定字符串分隔源数据,请提供所需的值作为第一个参数:

To separate the source data with a certain string, provide the desired value as the first argument:

string[] sourceData = new[] { "a", "b", "c" };
string separator = "-";
var result = string.Join(separator, sourceData);

现在字符串- 将为插入到源数据中每个项目之间: abc

Now the string "-" will be inserted between every item in the source data: "a-b-c".

最后,将项目中的每个项目包含或修改源集合,您可以使用:

Finally to enclose or modify each item in the source collection, you can use projection using Linq's Select() method:

string[] sourceData = new[] { "a", "b", "c" };
string separator = "-";
result = String.Join(separator, sourceData.Select(s => "[" + s + "]"));

代替 [ + s +] ,最好使用以提高可读性和易于修改: String.Format( [{0}],s )

无论哪种方式,也都返回期望的结果: [a]-[b]-[ c]

Either way, that also returns the desired result: "[a]-[b]-[c]".

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09-05 18:45