使用grep搜索多种模式的功能

问题描述

我想制作一个bash脚本，以使用grep搜索具有多个模式(不区分大小写)的行.我想创建一个bash脚本，可以按以下方式使用:

I want to make a bash script to use grep to search for lines which have multiple patterns (case-insensitive). I want to create a bash script which I can use as follows:

myscript file.txt pattern1 pattern2 pattern3

，它应该被翻译为:

grep -i --color=always pattern1 file.txt | grep -i pattern2 | grep -i pattern3

我尝试了以下bash脚本，但无法正常工作:

I tried following bash script, but it is not working:

#!/bin/bash
grep -i --color=always $2 $1 | grep -i $3 | grep -i $4 | grep -i $5 | grep -i $6 | grep -i $7

错误是:

Usage: grep [OPTION]... PATTERN [FILE]...
Try 'grep --help' for more information.
Usage: grep [OPTION]... PATTERN [FILE]...
Try 'grep --help' for more information.
Usage: grep [OPTION]... PATTERN [FILE]...
Try 'grep --help' for more information.
Usage: grep [OPTION]... PATTERN [FILE]...
Try 'grep --help' for more information.

推荐答案

我认为您可以执行递归功能:

I think you can do a recursive function:

search() {
    if [ $# -gt 0 ]; then
        local pat=$1
        shift
        grep "$pat" | search "$@"
    else
         cat
    fi
}

在脚本中，您将调用此函数并将搜索模式作为参数传递.假设 $ 1 是文件，其余参数是模式，那么您就可以这样做

In your script you would call this function and pass the search patterns as arguments. Say that $1 is the file and the rest of the arguments are patterns then you would do

file=$1
shift
cat "$file" | search "$@"

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