问题描述
我想让原产地与我的本地标签相匹配.这不要与修剪本地标签混淆，而是要修剪远程标签.
I would like to have origin match my local tags. This is not to be confuse with pruning local tags, but remote instead.
要修剪 local 标签并使我的本地存储库与来源匹配，我会这样做:
To prune local tags and make my local repository match origin I do:
git tag -l | xargs git tag -d
git fetch
我在本地清理了标签，我想推送和删除远程没有的内容.
I cleaned the tags locally and I would like to push and remove what is not up in remote.
我一直在手动操作，例如:
I have been doing it manually like:
git tag -l | grep -v "[^v2]" | xargs git tag -d # remove local tags that don't match a pattern
git push origin :refs/tags/2.2.15 # manually remove those tags on remote
git push origin :refs/tags/2.2.16
git push origin :refs/tags/2.2.17
git push origin :refs/tags/2.2.18
...
但是有这么多标签，我觉得这可以做不同的事情.那么问题是，如何从远程存储库中删除那些您本地没有的标签?
But with so many tag I feel like this could be done differently.Question is then, How to remove from a remote repository those tags that you do not have locally?
推荐答案
刚刚在远程仓库上测试过，效果很好.
Just tested it on a remote repo and it works fine.
我使用 cut 而不是 grep，并将远程标签与本地标签进行比较，然后删除不同的远程标签.
I used cut instead of grep, and compared the remote tags against the local ones, then removed the remote ones that differed.
git ls-remote --tags origin | cut -f 2 | xargs basename | comm -23 - <(git tag) | awk '{print ":refs/tags/" $0}' | xargs git push origin
不是世界上最优雅的东西，但它确实有效.
Not the most elegant thing in the world, but it works.
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