问题描述
我有一个URL列表，并且想确定什么是目录，什么不是:
I have a list of URLs, and would like to identify what is a directory and what is not:
https://www.example.com/folder/
https://www.example.com/folder9/
https://www.example.com/folder/file.sh
https://www.example.com/folder/text
我可以使用grep -e /$查找哪一个，但是我想执行一个内联命令，在该命令中我可以根据该逻辑重定向输出.
I can use grep -e /$ to find which is which, but I'd like to do an inline command where I can redirect the output based on that logic.
我知道awk在这里可能有答案，但是没有足够的awk经验来做到这一点.
I understand that awk may have the answer here, but don't have enough experience in awk to do this.
类似的东西:
cat urls | if /$ matches write to folders.txt else write to files.txt
我可以将所有内容放到一个文件中，然后读取两次，但是当到达数千行时，我觉得效率很低.
I could drop it all to a file then read it twice but when it gets to thousands of lines I feel that would be inefficient.
推荐答案
是的，awk是一个不错的选择:
Yes, awk is a great choice for this:
awk '/\/$/ { print > "folders.txt"; next }
{ print > "files.txt" }' urls.txt
-
/\/$/ { print > "folders.txt"; next }如果该行以/结尾，则将其写入folder.txt，然后跳至下一行 -
{ print > "files.txt" }将所有其他行写入files.txt /\/$/ { print > "folders.txt"; next }if the line ends with a /, write it to folders.txt and skip to the next line{ print > "files.txt" }write all other lines to files.txt
如果文件中有尾随空格，则可能要使用表达式/\/[[:space:]]*$/而不是/\/$/.
You may want to use the expression /\/[[:space:]]*$/ instead of /\/$/ in case you have trailing spaces in your file.
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