本文介绍了Python 3 ftplib错误“名称或服务未知"的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用Python 3的ftplib库从FTP服务器下载文件.

I am trying to download a file from FTP server using ftplib library of Python 3.

这是相关代码-

ftp = ftplib.FTP("ftp://library.daisy.org:21/User_****/Wise & Otherwise-22.zip")
ftp.login("xxxxx", "xxxxxxx")
ftp.cwd(path)
ftp.retrbinary("RETR " + filename, open(filename, 'wb').write)
ftp.quit()

当我尝试运行脚本时,出现以下错误-

When I try to run the script the following error shows up-

Traceback (most recent call last):
  File "reader.py", line 604, in <module>
    sp.process_user_choice()
  File "reader.py", line 72, in process_user_choice
    self.download_books()   File "reader.py", line 324, in download_books
    ftp = ftplib.FTP(all_urls[response])
  File "/usr/lib/python3.5/ftplib.py", line 118, in __init__
    self.connect(host)
  File "/usr/lib/python3.5/ftplib.py", line 153, in connect
    source_address=self.source_address)
  File "/usr/lib/python3.5/socket.py", line 694, in create_connection
    for res in getaddrinfo(host, port, 0, SOCK_STREAM):
  File "/usr/lib/python3.5/socket.py", line 733, in getaddrinfo
    for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno -2] Name or service not known


一些笔记-


Some notes-

  1. 我有正确的URL和凭据
  2. 我在代理服务器后面

推荐答案

顾名思义,FTP构造函数的host自变量仅接受一个主机名,例如library.daisy.org.您正在传递一个完整的URL.

The host argument of FTP constructor takes, as the name suggests, a hostname only, like library.daisy.org. You are passing in a whole URL.

这是正确的:

ftp = ftplib.FTP("library.daisy.org")


完整路径进入RETR命令的参数:


The full path goes to an argument of the RETR command:

ftp.retrbinary("RETR User_****/Wise & Otherwise-22.zip", open(filename, 'wb').write)


通过代理连接时,您也必须满足这一要求.


As you are connecting via proxy, you have to cater for that too.

这里涉及到很多问题.但是您没有告诉我们您使用的是哪种代理,所以我不能更具体地说明了.

There are lot of questions here covering that part. But you didn't tell us what kind of proxy you are using, so I cannot be more specific.

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09-05 18:03