我可以将整个字符串作为一个命令行参数传递给C中的argv吗?

问题描述

说我有一个像这样的程序:

Say I have a program like this:

int main(int argc, char **argv){
    printf("The name of the program is %s, and the string passed is:\n %s \n\n", argv[0], argv[1]);
    return 0;
}

我意识到应该进行错误检查等等，但是我真正想知道的是如何将整个字符串作为第一个参数传递，或者甚至可以传递.谢谢！

I realize there should be error checking and whatnot, but what I'd really like to know is how to pass a whole string as the first argument or if it's even possible. Thanks!

推荐答案

只需使用引号

./file_name "This is the long string argument that comes in argv[1]"
     |
     |
     +--- argv[0]

---

修改:

aruisdante:

aruisdante: single and double quotes are treated depending on the shell, double quotes might do unexpected things

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