如何串联XML文件中的相似标签

问题描述

单个XML记录集中可以有一个或多个类似的XML标签.如果有很多，我需要将它们放在一个标签中，以逗号分隔.这是我现在拥有的XML.

There can be one or many similar XML tags inside a single XML record set. If there are many, I need them to be in a one tag, comma separated.This is the XML I have now.

<?xml version="1.0"?>
    <Results>
        <Recordset setCount="3">

            <Record setEntry="0">
                <AU>One</AU>
                <AU>Two</AU>
                <AU>three</AU>
            </Record>

            <Record setEntry="1">
                <AU>One</AU>
                <AU>Two</AU>
                <AU>Three</AU>
                <AU>Four</AU>
                <AU>Five</AU>
                <AU>Six</AU>
                <AU>Seven</AU>
            </Record>

            <Record setEntry="2">
                <AU>One</AU>
            </Record>

        </Recordset>
    </Results>

我需要像这样.请提供代码帮助.

I need it to be like this. Please help with a code.

<?xml version="1.0"?>
<Results>
<Recordset setCount="3">

<Record setEntry="0">
<AU>One, Two, Three</AU>
</Record>

<Record setEntry="1">
<AU>One, Two, Three, Four, Five, Six, Seven</AU>
</Record>

<Record setEntry="2">
<AU>One</AU>
</Record>

</Recordset>
</Results>

推荐答案

这可以通过xpath完成.这是 Simplexml 的示例:

This can be done with xpath. Here is an example with Simplexml:

您可以首先找到所有第一个叶子:

You can first find all the first leafs:

foreach ($xml->xpath('//*[not(*) and not(preceding-sibling::*)]') as $firstLeaf) {
    ...
}

然后将文本与以下所有叶子合并在一起:

and then you concat the text together with all the following leafs:

    $followingWithSameName = 'following-sibling::*[name(.) = name(preceding-sibling::*[last()])]';
    // change the text of the first leaf
    $firstLeaf[0] = implode(', ', $firstLeaf->xpath(".|$followingWithSameName"));

，然后删除以下所有叶子:

and then you remove all the following leafs:

    // remove all following leafs with the same name
    foreach ($firstLeaf->xpath($followingWithSameName) as $leaf) {
        unset($leaf[0]);
    }

演示

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