问题描述
我希望使用Opencv卡尔曼滤波器实现来平滑某些噪声点.因此，我尝试为此编写一个简单的测试.
I wan to use Opencv Kalman filter implementation for smooth some noise points. So I've tried to code a simple test for it.
假设我有一个观察点(观点).我收到新的观察结果的每一帧，我称卡尔曼预测和卡尔曼正确. opencv卡尔曼滤波器正确之后的状态是跟随该点"，这是可以的.
Let's say I have an observation (a point). Each frame I'm receiving new observation, I call Kalman predict and Kalman correct. The state coming after opencv Kalman filter correct is "following the point", it is ok.
然后，假设我有一个缺失的观测值，无论如何我都希望更新卡尔曼滤波器并预测新状态.这里的代码失败了:如果我调用kalman.predict()，该值将不再更新.
Then let's say I have a missing observation, I want anyway the Kalman filter to be updated and predict the new state. Here my code is failing: if I call kalman.predict() the value is no more updated.
这是我的代码:
#include <iostream>
#include <vector>
#include <sys/time.h>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/video/tracking.hpp>
using namespace cv;
using namespace std;
//------------------------------------------------ convenience method for
// using kalman filter with
// Point objects
cv::KalmanFilter KF;
cv::Mat_<float> measurement(2,1);
Mat_<float> state(4, 1); // (x, y, Vx, Vy)
void initKalman(float x, float y)
{
// Instantate Kalman Filter with
// 4 dynamic parameters and 2 measurement parameters,
// where my measurement is: 2D location of object,
// and dynamic is: 2D location and 2D velocity.
KF.init(4, 2, 0);
measurement = Mat_<float>::zeros(2,1);
measurement.at<float>(0, 0) = x;
measurement.at<float>(0, 0) = y;
KF.statePre.setTo(0);
KF.statePre.at<float>(0, 0) = x;
KF.statePre.at<float>(1, 0) = y;
KF.statePost.setTo(0);
KF.statePost.at<float>(0, 0) = x;
KF.statePost.at<float>(1, 0) = y;
setIdentity(KF.transitionMatrix);
setIdentity(KF.measurementMatrix);
setIdentity(KF.processNoiseCov, Scalar::all(.005)); //adjust this for faster convergence - but higher noise
setIdentity(KF.measurementNoiseCov, Scalar::all(1e-1));
setIdentity(KF.errorCovPost, Scalar::all(.1));
}
Point kalmanPredict()
{
Mat prediction = KF.predict();
Point predictPt(prediction.at<float>(0),prediction.at<float>(1));
return predictPt;
}
Point kalmanCorrect(float x, float y)
{
measurement(0) = x;
measurement(1) = y;
Mat estimated = KF.correct(measurement);
Point statePt(estimated.at<float>(0),estimated.at<float>(1));
return statePt;
}
//------------------------------------------------ main
int main (int argc, char * const argv[])
{
Point s, p;
initKalman(0, 0);
p = kalmanPredict();
cout << "kalman prediction: " << p.x << " " << p.y << endl;
/*
* output is: kalman prediction: 0 0
*
* note 1:
* ok, the initial value, not yet new observations
*/
s = kalmanCorrect(10, 10);
cout << "kalman corrected state: " << s.x << " " << s.y << endl;
/*
* output is: kalman corrected state: 5 5
*
* note 2:
* ok, kalman filter is smoothing the noisy observation and
* slowly "following the point"
* .. how faster the kalman filter follow the point is
* processNoiseCov parameter
*/
p = kalmanPredict();
cout << "kalman prediction: " << p.x << " " << p.y << endl;
/*
* output is: kalman prediction: 5 5
*
* note 3:
* mhmmm, same as the last correction, probabilly there are so few data that
* the filter is not predicting anything..
*/
s = kalmanCorrect(20, 20);
cout << "kalman corrected state: " << s.x << " " << s.y << endl;
/*
* output is: kalman corrected state: 10 10
*
* note 3:
* ok, same as note 2
*/
p = kalmanPredict();
cout << "kalman prediction: " << p.x << " " << p.y << endl;
s = kalmanCorrect(30, 30);
cout << "kalman corrected state: " << s.x << " " << s.y << endl;
/*
* output is: kalman prediction: 10 10
* kalman corrected state: 16 16
*
* note 4:
* ok, same as note 2 and 3
*/
/*
* now let's say I don't received observation for few frames,
* I want anyway to update the kalman filter to predict
* the future states of my system
*
*/
for(int i=0; i<5; i++) {
p = kalmanPredict();
cout << "kalman prediction: " << p.x << " " << p.y << endl;
}
/*
* output is: kalman prediction: 16 16
* kalman prediction: 16 16
* kalman prediction: 16 16
* kalman prediction: 16 16
* kalman prediction: 16 16
*
* !!! kalman filter is still on 16, 16..
* no future prediction here..
* I'm exprecting the point to go further..
* why???
*
*/
return 0;
}
我认为这段代码很好地说明了我所不了解的内容.我试图遵循一些理论和一些，但请不要误解如何获得对未来头寸的新预测.
I think that this code is quite illustrative of what I don't understand. I've tried to follow some theory and some practical example but don't still unserstand how to get new prediction of the future position..
任何人都可以帮助我了解我在做什么错吗?
Anyone can help me in understand what I'm doing wrong?
推荐答案
我没有设置转换和度量矩阵.
I didn't set the transition and measurement matrix.
我在优秀MATLAB文档页面.
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