NHibernate 3.2通过代码映射IDictionary | 2通过代码映射IDictionary

本文介绍了NHibernate 3.2通过代码映射IDictionary的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

在使用新的Loquacious配置映射到IDictionary时遇到问题.

I'm having a problem mapping to IDictionary using the new Loquacious configuration.

这是课程:

public class Person
{
    public Person()
    {
        Description = new Dictionary<int, string>();
    }

    public virtual int Id { get; set; }

    // can be in various languages
    public virtual IDictionary<int, string> Resources { get; set; }
}

public class PersonResource
{
    public virtual string Description { get; set; }
}

以下是映射:

public class TestPersonMap : ClassMapping<TestPerson>
{
    Table("TestPersons");

    Id(c => c.Id, m => m.Generator(Generators.HighLow, gm => gm.Params(new { max_low = 1000 })));

    Map(c => c.Resources, mpm =>
                                {
                        mpm.Table("TestPersonResources");
                        mpm.Key(km => km.Column("Id"));
                     },
            mkr => mkr.Component(cem => cem.Property(p => p.Description)));

这将在数据库中生成一个表，如下所示:

This produces a table in the database like this:

TestPersons
-----------
Id

TestPersonResources
-------------------
Id
Description
idx

问题是，如何将TestPersonResources表中'idx'列的名称更改为Lcid?

The question is, how do I change the name of the 'idx' column in the TestPersonResources table to Lcid?

我尝试查看此示例 http://code.google.com/p/codeconform/source/browse/ConfOrm/ConfOrm.UsageExamples/ComponentAsDictionaryKey/Demo.cs

但是我似乎无法将其应用于我的问题.

But I can't seem to apply it to my problem.

提前谢谢！

推荐答案

在弄乱并仔细查看NHibernate源代码后，我认为我终于使它工作了.这是我所做的:

After messing around and looking harder at the NHibernate source code, I think I finally got it working. Here's what I did:

Map(c => c.Resources, mpm =>
                            {
                    mpm.Key(km => km.Column("Id"));
                    mpm.Table("TestPersonResources");
                },
            mkr => mkr.Element(mkm => mkm.Column("Lcid")),
            cer => cer.Component(cem => cem.Property(p => p.Description, pm => pm.Length(100))));

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