JSON-如何从JavaScript文件中获取详细信息在javascript中编码JSON数据？

问题描述

details.js

details.js

$(document).ready(function()
{
    $.ajax({
        url: 'js/index.php',
        dataType: 'jsonp',
        jsonp: 'callback',
        timeout: 5000,
        success: function(data){
            $.each(data, function(key,val){
                console.log(val.NAME);
            });
        },
        error: function(){
            alert('There was an error loading the data.');
        }
    });
});

index.php

index.php

<?php
if($_SERVER['REQUEST_METHOD']=="GET")
{
$callback= $_GET['callback'] ;
$db=mysqli_connect("localhost","username","password","detail")or die (" error connection");
$d = mysqli_query($db, "select * from data") or die ("Query error");

while($m = mysqli_fetch_assoc($d))
$output[]=$m;
mysqli_close($db);
$data= json_encode($output);
echo $callback.'('.$data.')';
?>

我正在创建一个cordova应用程序其中我需要从php文件index.php获取数据，详细信息来自数据库mysql。与mysql的连接和插入值等完美完成，这些细节编码为json格式： -

[{ID：1，NAME：abc}] - 这个php文件输出正确显示



现在我需要在javascript文件中获取这些值。我已经尝试了上面的代码，但是在控制台'NAME'中没有显示或者我无法获取详细信息。我怎么能解决这个问题。

任何人都可以帮助我。

I am creating a cordova application in which i need to get the data from a php file index.php ,details are taken from database mysql.The connection with mysql and inserting values etc is perfectly done and these details are encoded to json format:-
[{"ID":"1","NAME":"abc"}]-this output of php file is displayed properly

Now i need to get these values in a javascript file.I have tried the above code,but in the console 'NAME' for example is not displayed or I couldn't get the details.How can i solve this.
Can anybody please help me in this.

推荐答案

index.php

index.php

<?php
if(

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