本文介绍了尝试访问类中的属性时,为什么会出现NameError?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个带有此类的代码:
I have this code with a class:
class Triangle(object):
def __init__(self, side1, side2, side3):
self.side1 = side1
self.side2 = side2
self.side3 = side3
def perimeter(self):
return "Perimeter = %s" % (side1 + side2 + side3)
a = Triangle(3, 4, 5)
print(a.perimeter())
运行此代码将引发异常:
Running this code throws an exception:
Traceback (most recent call last):
File "untitled.py", line 12, in <module>
print(a.perimeter())
File "untitled.py", line 9, in perimeter
return "Perimeter = %s" % (side1 + side2 + side3)
NameError: name 'side1' is not defined
为什么我无法通过perimeter
方法访问side1
?
How come I can't access side1
in the perimeter
method?
推荐答案
替换
return "Perimeter = %s" %(side1 + side2 + side3)
收件人
return "Perimeter = %s" %(self.side1 + self.side2 + self.side3)
您错过了添加self
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