getElementsByTagName向下搜索所有级别的XML节点

问题描述

我有这个XML文件：

<root>
    <node1>
        <name>A</name>
        <node2>
            <name>B</name>
            <node3>
                <name>C</name>
                <number>001</number>
            </node3>
        </node2>
    </node1>
</root>

我正在解析文件，以获取每个节点的名称以及相应的编号（如果存在）。

I am parsing the file, to get the name for each node, and the corresponding number if existing.

我使用：

String number = eElement.getElementsByTagName("number").item(0).getTextContent();

这应该给我类似的东西：

This should give me something like:

Name | Number
A    |
B    |
C    | 001

但是我得到：

Name | Number
A    | 001
B    | 001
C    | 001

所以，我认为 getElementsByTagName（ Number）在节点的所有子节点中寻找数字节点。我不要有人知道解决方法吗？

So, I think the getElementsByTagName("Number") is looking for number node in all the children of a node. I don't want that. Does anybody know a workaround?

我想到了使用XPath代替上述方法，但是我真的很想知道是否存在现有方法。谢谢

I thought of using XPath instead of the above method, but I really want to know if there's an existing way. Thanks

推荐答案

您可以使用 javax.xml.xpath API JDK / JRE对通过 getElementsByTagName 返回的XML进行更多控制。

You can use the javax.xml.xpath APIs in the JDK/JRE to have much more control over the XML returned over getElementsByTagName.

import java.io.File;
import javax.xml.parsers.*;
import javax.xml.xpath.*;
import org.w3c.dom.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
        Document document = docBuilder.parse(new File("filename.xml"));

        XPathFactory xpathFactory = XPathFactory.newInstance();
        XPath xpath = xpathFactory.newXPath();
        Element element = (Element) xpath.evaluate("//node3/name", document, XPathConstants.NODE);
    }

}

这篇关于getElementsByTagName向下搜索所有级别的XML节点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！