如何在python pycrypto中指定RSA填充

本文介绍了如何在python pycrypto中指定RSA填充的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 我得到了一些Java RSA解密代码，现在我想用Python pycrypto表示。 ，但是我使用了相同的私钥，但是得到了不同的密文，并且服务器只访问了用Java加密的密文。I got a pice of java RSA decrypt code, now I want to express in Python pycrypto.but I got different ciphertext although using same private key, and server only access ciphertext that encrypt by java.我sea着谷歌，看起来像是填充的原因 我不熟悉RSA，我目前的解决方案是在tomcat中执行Java代码，Python通过http请求调用它。I seach google, it look like cause of padding.I am not familiar with RSA, my current solution is that execute java code in tomcat, Python call it through http request.但是我仍然希望直接在Python代码中进行加密。but I still want to encrypt direct in Python code.在Java代码中：public static String encrypt(String paramString)throws Exception{ return Base64Utils.encode(RSAUtils.encryptByPrivateKey(paramString.getBytes(), "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"));}public static byte[] encryptByPrivateKey(byte[] paramArrayOfByte, String paramString)throws Exception{ paramString = new PKCS8EncodedKeySpec(Base64Utils.decode(paramString)); paramString = KeyFactory.getInstance("RSA").generatePrivate(paramString); Cipher localCipher = Cipher.getInstance("RSA/ECB/PKCS1Padding");//like this padding localCipher.init(1, paramString); int k = paramArrayOfByte.length; ByteArrayOutputStream localByteArrayOutputStream = new ByteArrayOutputStream(); int j = 0; int i = 0; if (k - j > 0) { if (k - j > 117) {} for (paramString = localCipher.doFinal(paramArrayOfByte, j, 117);; paramString = localCipher.doFinal(paramArrayOfByte, j, k - j)) { localByteArrayOutputStream.write(paramString, 0, paramString.length); i += 1; j = i * 117; break; } } paramArrayOfByte = localByteArrayOutputStream.toByteArray(); localByteArrayOutputStream.close(); return paramArrayOfByte;} 在Python代码中：in Python code:from Crypto.PublicKey import RSAfrom Crypto.Cipher import PKCS1_v1_5from base64 import b64decode, b64encodedef encrypt(msg): key = "MIICdgIBADANBgkqhkiG9w0BAQEFA..." key = b64decode(key) private_key = RSA.importKey(key) cipher = PKCS1_v1_5.new(private_key) return b64encode(cipher.encrypt(msg))java.encrypt("159742081"):first time: GBn6RGIeEp8j/n35CgT5DdMmrvvNBtVCFQikO0vfJaYYrpEzBZ/F+5PkFLpzLDtYvQrj0Q/x/Fdxz3BtbEdLq57WFxB5MvkFxerWVeplA2vdlD7m+dgjsWyxBSbcVV1QX3UBNp+T3DtxL6uGuWUNxucy9yB5TOD3xCNchzGCnSU=second time: GBn6RGIeEp8j/n35CgT5DdMmrvvNBtVCFQikO0vfJaYYrpEzBZ/F+5PkFLpzLDtYvQrj0Q/x/Fdxz3BtbEdLq57WFxB5MvkFxerWVeplA2vdlD7m+dgjsWyxBSbcVV1QX3UBNp+T3DtxL6uGuWUNxucy9yB5TOD3xCNchzGCnSU=python.encrypt('159742081'):first time:K5VXCDAPZ5yg0/UFT6mLdDOlYAI0n15HR9I60ZMntyHIItUDK7mnb67oX5BzZpx+j6OH8nfeZFPPfxRKpk83m4uN7Gw0TZTuN0eajRa2Jg79ctumBqmzCQM/05UH3wCMouVbvFu31O4PLBHqcmJNuJCOiAJE98wMKIwdS7ewv/4second time:UWWdt1WcI0UOovXb7hH1CqK0RJWSJ4uVCOJ0wjtzPu8JB1cAOu+JaWDBjh6PMWWdi6Osb2cnOddYdgUHoMiTUieAIbj2jaXXxKzxaNlqDAGNRLZUthZXqMPEdpZ91Jagus9OS/soJBP/Vkz6i1lqpriDsm5CqVsSr+Bz+Ro7+Vo=对于相同的明文，java.encrypt返回相同的密文，但是python.encrypt每次都返回不同的密文。for same plaintext, java.encrypt return same ciphertext, however python.encrypt return different ciphertext in everytime.推荐答案我绝对没有得到您要在Java代码中执行的操作，但是它没有正确执行。I absolutely don't get what you're trying to do in the Java code, but it is not going right. PKCS＃1 v1.5加密填充使用至少8个字节设置为1..255范围内的随机值。这意味着模幂运算后的结果在0到N（模数）的范围内是完全随机的。因此，每次使用Java或Python进行加密时，结果应该是完全随机的。密码必须是IND_CPA安全的，这是必需的；PKCS#1 v1.5 padding for encryption uses at least 8 bytes set to a random value in the range 1..255. This means that the outcome after modular exponentiation is completely random within the range 0 to N (the modulus). So each time you encrypt, using either Java or Python, the result should be completely random. This is required for the cipher to be IND_CPA secure; you would distinguish between two identical plaintext otherwise.有一种测试加密的好方法：将其解密并查看是否获得相同的二进制明文。您应该能够测试该跨平台。There is one good way to test encryption: decrypt it and see if you get the same binary plaintext. You should be able to test this cross-platform. 这篇关于如何在python pycrypto中指定RSA填充的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！