本文介绍了将datefinder的输出放入列表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
import datefinder
import pandas as pd
s = "entries are due by January 4th, 2017 at 8:00pm. created 01/15/2005 by ACME Inc. and associates. here Dec. 24th, 1981 at 6pm."
match = datefinder.find_dates(s)
for m in match:
print(m)
2017-01-04 20:00:00
2005-01-15 00:00:00
1981-12-24 18:00:00
以上方法使用datefinder来查找字符串中的日期.例如，从s抓取January 4th, 2017 at 8:00pm并将其转换为2017-01-04 20:00:00.现在，我只想获取输出print(m)并将其转换为包含与相同格式的列表mm.我用
The above works using datefinder to find dates in string. For example, January 4th, 2017 at 8:00pm is grabbed from s and is converted into 2017-01-04 20:00:00. Now I simply want to get the output print(m) and turn it into a list mm which contains the same format as print(m). I use
mm = []
for m in match:
d = pd.Series(m)
mm.append(m)
mm
[datetime.datetime(2017, 1, 4, 20, 0),
datetime.datetime(2005, 1, 15, 0, 0),
datetime.datetime(1981, 12, 24, 18, 0)]
但我希望输出为
mm
[2017-01-04 20:00:00,
2005-01-15 00:00:00,
1981-12-24 18:00:00]
我该如何更改我的代码?
How do I change my code to do so?
推荐答案
在print(m)上，将其更改为print(m.strftime("%Y-%m-%d %H:%M:%S")). strftime用于将datetime对象转换为字符串.
On print(m), change it to print(m.strftime("%Y-%m-%d %H:%M:%S")). strftime is designed to convert datetime objects into strings.
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