转换字节字符串的计划，以INT

问题描述

我有code这样的转换为十六进制字节的字符串

I have code like this to convert hex into byte string

(define (word->bin s)
  (let ((n (string->number s)))
    (bytes (bitwise-and (arithmetic-shift n -24) #xFF)
    (bitwise-and (arithmetic-shift n -16) #xFF)
    (bitwise-and (arithmetic-shift n -8) #xFF)
    (bitwise-and n #xFF))))
(word->bin "#x10000002")

我在想一个类似的功能将二进制转换成整数，然后打印出来。最终的结果是转换为十六进制二进制。一些有用的链接：的

I'm thinking of a similar function to convert binary into integers, then print it. The end result is the binary translated to hex. Some helpful links:http://download.plt-scheme.org/doc/372/html/mzscheme/mzscheme-Z-H-11.html#node_sec_11.2.1

http://docs.plt-scheme.org/reference/bytestrings.html#(def.((quote.~23~25kernel)._bytes-~3estring/utf-8))

http://docs.plt-scheme.org/reference/bytestrings.html#(def.((quote.~23~25kernel)._bytes-~3estring/utf-8))

推荐答案

我不知道这是你要找的东西，或者即使你使用的，但如果这样做，那么你应该看看整数bytes-＆GT;的整数和整型＆GT;的整数，字节函数是在PLT包括。请注意，这些创建字节串用的二的内容 - 因此它可能比你想在这里做什么不同的

I'm not sure that this is what you're looking for, or even if you're using PLT, but if you do, then you should look at the integer-bytes->integer and integer->integer-bytes functions that are included in PLT. Note that these create byte strings with binary content -- so it might be different than what you're trying to do here.

（如果你使用的是372版本，那么你就应该升级。）

(And if you're using version 372, then you should really upgrade.)

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