python 2中默认使用哈希方法，而不是python 3中默认

问题描述

在将某些代码从python 2转换为python 3时，我遇到了一个奇怪的行为示例.以下是它的一个最小(?)示例:

I've come across an example of weird behavior when transitioning some code from python 2 to python 3. Below's a minimal (?) example of it:

class Bar(object):
    def __init__(self, x):
        self.x = x
    def __eq__(self, other):
        return self.x == other.x

b = Bar(1)
print(hash(b))

与python2一起运行时，此代码会产生一些输出(Bar(1)的哈希)，而python3会导致TypeError: unhashable type: 'Bar'

when run with python2, this code produces some output (a hash of Bar(1)), while python3 causes a TypeError: unhashable type: 'Bar'

这意味着__hash__是在python 2中以某种方式继承的(从object吗?).

this means that __hash__ is somehow inherited (from object ?) in python 2.

所以，我的问题是:python 2中Bar(1)的哈希是什么?为什么行为不同?

So, my questions are: what is the hash of Bar(1) in python 2? And why is the behaviour different?

推荐答案

是的，数据模型已更改. 在Python 3中:

Yes, the data model has changed. In Python 3:

覆盖__eq__()并且未定义__hash__()的类将其__hash__()隐式设置为None .当...的时候 类的__hash__()方法是None，当程序尝试检索时，该类的实例将引发适当的TypeError. 它们的哈希值，也将正确地标识为不可哈希 检查isinstance(obj, collections.abc.Hashable)时.

A class that overrides __eq__() and does not define __hash__() will have its __hash__() implicitly set to None. When the __hash__() method of a class is None, instances of the class will raise an appropriate TypeError when a program attempts to retrieve their hash value, and will also be correctly identified as unhashable when checking isinstance(obj, collections.abc.Hashable).

因此，由于您已明确定义了__eq__，但未定义__hash__，因此Python 3对象将隐式具有__hash__ = None，从而导致这些对象不可散列

So, since you've defined a __eq__ explicitely, but did not define a __hash__, Python 3 objects will implicitely have __hash__ = None, causing the objects to be unhashable

在 Python 2 中:

因此它是基于身份的哈希，这是一个问题，因为它与您的__eq__不一致.这是Python 3切换行为的原因.

So it is hashing based on identity, which is a problem, because it isn't consistent with your __eq__. This is a reason that Python 3 switched behaviors.

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