从python中的字典列表中选择一个字段

从python中的字典列表中选择一个字段

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问题描述

让我说我有一个这样的字典列表:

  dictionList = {1:{'Type':'Cat ','Legs':4},
2:{'Type':'Dog','Legs':4},
3:{'Type':'Bird','Legs' 2}}

使用for循环我想迭代列表,直到我找到一个字典类型字段等于
我最好的尝试是:

  for d in dictionList:
如果dictionList(i ['Type' ])==狗:
打印找狗!

但是这会让我出现以下错误:

  TypeError:'int'对象没有属性'__getitem__'

任何关于如何正确执行此操作的想法?

解决方案

使用 iterator for dictionaries:

  for v in dictionList.values():
if v ['Type'] =='狗':
打印找到一只狗!

编辑:我会说,在你的原始问题,你要求查看键入字典中的值,这有点误导。您要求的是名为Type的的内容。这可能是一个微妙的区别,以了解你想要什么,但它是一个相当大的差异在程序设计。



在Python中,你应该只有RARELY需要键入 - 检查任何东西。


Lets say I have a list of dictionaries like so:

dictionList = {1: {'Type': 'Cat', 'Legs': 4},
               2: {'Type': 'Dog', 'Legs': 4},
               3: {'Type': 'Bird', 'Legs': 2}}

Using a for loop I want to iterate through the list until I catch a dictionary with a Type field equal to "Dog".My best attempt was:

 for i in dictionList:
     if dictionList(i['Type']) == "Dog":
         print "Found dog!"

But that gets me the following error:

TypeError: 'int' object has no attribute '__getitem__'

Any ideas on how to properly do this?

解决方案

Use the values iterator for dictionaries:

for v in dictionList.values():
    if v['Type']=='Dog':
         print "Found a dog!"

EDIT: I will say though that in your original question you are asking to check the Type of a value in a dictionary, which is somewhat misleading. What you are requesting is the content of a value called 'Type'. This may be a subtle difference to understanding what you want, but it is a rather large difference in terms of programming.

In Python, you should ever only RARELY need to type-check anything.

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09-05 10:00