本文介绍了指针和字符串分割造成的故障的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
char *str = "Hello";
printf("%c",++*str);
This gives segmentation fault on linux with gcc.The moment the first statement is changes to as
char str[10] = "Hello";
It works. What may be the reason?
解决方案
It is undefined behaviour to attempt to modify a string literal.
The compiler is free to place it in read-only memory (as it probably does in your case). Attempting to modify read-only memory is what's probably triggering the segfault.
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