问题描述
data=data.frame("Student"=c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),
"Grade"=c(5,6,7,3,4,5,4,5,6,8,9,10,2,3,4),
"Pass"=c(NA,0,1,0,1,1,0,1,0,0,NA,NA,0,0,0),
"NEWPass"=c(0,0,1,0,1,1,0,1,1,0,0,0,0,0,0),
"GradeNEWPass"=c(7,7,7,4,4,4,5,5,5,10,10,10,4,4,4),
"GradeBeforeNEWPass"=c(6,6,6,3,3,3,4,4,4,10,10,10,4,4,4))
我有一个名为data的data.frame.它的列名称为学生",成绩"和及格".我希望这样做:
I have a data.frame called data. It has column names Student, Grade and Pass. I wish to do this:
NEWPass:持有通行证,并为每个学生使用先前的值填写NA值.如果第一个值为"NA",则放置零.那么这应该是运行的最大值.
NEWPass: Take Pass and for every Student fill in NA values with the previous value. If the first value is 'NA' than put a zero. Then this should be a running maximum.
GradeNEWPass:采用学生在NEWPass中获得的最低成绩.如果学生未在NEWPass中获得1分,则等于最高成绩.
GradeNEWPass: Take the lowest value of Grade that a Student got a one in NEWPass. If a Student did not get a one in NEWPass, this equals to the maximum grade.
GradeBeforeNEWPass:在学生获得NEWPass分数之前,取分数的价值.如果学生未在NEWPass中获得1分,则等于最高成绩.
GradeBeforeNEWPass: Take the value of Grade BEFORE a Student got a one in NEWPass. If a Student did not get a one in NEWPass, this equals to the maximum grade.
__尝试:
setDT(data)[, NEWPassTry := cummax(Pass), by = Student]
data$GradeNEWPass = data$NEWPassTry * data$Grade
data[, GradeNEWPass := min(GradeNEWPass), by = Student]
推荐答案
我们可以使用data.table
方法.按学生"分组,创建一个索引("i1"),其中通过"为1,而不是NA,然后使用which
和head
('i2')获得第一个位置1,同时计算max
of'Grade'('mx'),然后根据索引创建三列('v1'-获取二进制的累积最大值,'v2'-if
有any
1s,然后索引为'i2'或else
的'Grade'子集返回'mx',类似地为'v3'-将索引减去1得到'Grade'值
We can use data.table
methods. Grouped by 'Student', create an index ('i1') where the 'Pass' is 1 and not an NA, then get the first position of 1 with which
and head
('i2'), while calculating the max
of 'Grade' ('mx'), then create the three columns based on the indexes ('v1' - get the cumulative maximum of the binary, 'v2' - if
there are any
1s, then subset the 'Grade' with the index 'i2' or else
return 'mx', similarly 'v3'- the index is subtracted 1 to get the 'Grade' value
library(data.table)
setDT(data)[, c('NEWPass1', 'GradeNEWPass1', 'GradeBeforeNEWPass1') :={
i1 <- Pass == 1 & !is.na(Pass)
i2 <- head(which(i1), 1)
mx <- max(Grade, na.rm = TRUE)
v1 <- cummax(+(i1))
v2 <- if(any(i1)) Grade[i2] else mx
v3 <- if(any(i1)) Grade[max(1, i2-1)] else mx
.(v1, v2, v3)}, Student]
data
# Student Grade Pass NEWPass GradeNEWPass GradeBeforeNEWPass NEWPass1 GradeNEWPass1 GradeBeforeNEWPass1
# 1: 1 5 NA 0 7 6 0 7 6
# 2: 1 6 0 0 7 6 0 7 6
# 3: 1 7 1 1 7 6 1 7 6
# 4: 2 3 0 0 4 3 0 4 3
# 5: 2 4 1 1 4 3 1 4 3
# 6: 2 5 1 1 4 3 1 4 3
# 7: 3 4 0 0 5 4 0 5 4
# 8: 3 5 1 1 5 4 1 5 4
# 9: 3 6 0 1 5 4 1 5 4
#10: 4 8 0 0 10 10 0 10 10
#11: 4 9 NA 0 10 10 0 10 10
#12: 4 10 NA 0 10 10 0 10 10
#13: 5 2 0 0 4 4 0 4 4
#14: 5 3 0 0 4 4 0 4 4
#15: 5 4 0 0 4 4 0 4 4
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