使用javascript以特定顺序对具有十进制值的数组进行排序

问题描述

我有一个数组:

let arr = ['100.12', '100.8', '100.11', '100.9'];

排序后得到输出:

'100.11',
'100.12',
'100.8',
'100.9',

但是我希望它能像页面索引一样进行排序:

But I want it to be sorted like page indexing :

'100.8',
'100.9',
'100.11',
'100.12',

---

我几乎没有好的解决方案，但是他们缺乏一个地方，例如:arr1 = ['100.12', '77.8', '88', '77.11', '77.12', '77.9', '77', '119', '120', '100.8', '100.11', '100', '100.9']

---

I have got few good solution but they are lacking at one place ex:arr1 = ['100.12', '77.8', '88', '77.11', '77.12', '77.9', '77', '119', '120', '100.8', '100.11', '100', '100.9']

结果将是:

["77.8", "77.9", "77.11", "77.12", "77", "88", "100.8", "100.11", "100.12", "100", "100.9", "119", "120"]

这里应该是:

[ "77", "77.8", "77.9", "77.11", "77.12", "88", "100", "100.8", "100.11", "100.12", "100.9", "119", "120"]

推荐答案

您可以将string#localeCompare与numeric属性一起使用，以根据数值对数组进行排序.

You can use string#localeCompare with numeric property to sort your array based on the numeric value.

let arr = ['100.12', '77.8', '88', '77.11', '77.12', '77.9', '77', '119', '120', '100.8', '100.11', '100', '100.9'];
arr.sort((a, b) => a.localeCompare(b, undefined, {numeric: true}))
console.log(arr)

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