问题描述
我需要运行顺序在守护进程模式两个命令（命令将输出stderr上错误）。问题是，即使我在倾倒的/ dev / null的所有的输出，第二个命令（run_cmd2）不能被调用。这里是我的脚本
I need to run two commands sequentially in daemon mode (the commands will output the errors on stderr). The problem is that even I dump all the output in /dev/null, the second command (run_cmd2) cannot be invoked. Here is my script
#! /bin/bash
nohup ./run_cmd1 &> /dev/null &
nohup ./run_cmd2 &> /dev/null &
任何想法？先谢谢你。
Any ideas? Thank you in advance.
推荐答案
如何使用文件进行通信的状态？
How about using a file to communicate state?
run_cmd2会等到一个文件存在运行前
run_cmd2 will wait until a file exists before running
当run_cmd1完成后，它会创建表示文件。
when run_cmd1 is done, it will create the said file.
在其运行run_cmd2将删除该文件的结尾，所以run_cmd1可以再次运行
at the end of its run the run_cmd2 will delete the file, so run_cmd1 can run again
或者他们使用端口相互交谈？
Or maybe they talk to each other using a port?
也许一个信号？
有关详细信息：
这篇关于在bash脚本按顺序运行命令的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！