问题描述
对于这个基本问题很抱歉,但我试图在 R 中使用 sqldf 函数运行以下代码,但每次它都显示result_create(conn@ptr, statement) 中的错误: 附近")': 语法错误",我找不到错误的确切位置.
Sorry for the basic question, but I am trying to run the following code with sqldf function in R, but every time it shows "Error in result_create(conn@ptr, statement) : near ')': syntax error" and I can't find exactly where the error is.
我尝试以不同的方式缩进/格式化,但接近 ')'"的错误指示一直存在.
I tried to indent/format in different ways but the error indication to "near ')'" persists all the time.
似乎所有括号都可以.
代码:
sqldf("
SELECT Cia_2, Nombre_cia_2, N_orden_2, Tipo_orden_2, N_linea_2, N_direc_2, Nombre_alfa_2, Fecha_orden_2,
Surtido_programado_2, Original_prometida_2,
N_orden, Tipo_orden, N_linea, Cia,
Cant_recibida_2, Cant_pendiente_2, Cantidad_2, estado_sig_2, estado_ult_2,
(case when [N_orden_2] is null then 'SinOC' else 'ConOC' end) as TieneOC,
(case when [Cant_recibida_2]=0 and [Cant_pendiente_2]=0 and [estado_sig_2]=999 then 'Anulada'
else (case when [Cant_recibida_2] = [Cantidad_2] and [estado_sig_2] = 999 and [Tiene_OC_2] = 'SinOC' then 'Anulada' else 'NoAnulada' )) as Anulada,
(case when [N_direc_2] = 35999999 then 'Normal'
else (case when [N_direc_2] = 35999998 then 'Urgente'
else (case when [N_direc_2] = 35999997 then 'Emergente'
else (case when [N_direc_2] = 35999995 then 'Proyecto'
else (case when [N_direc_2] = 35999994 then 'Importaciones' else 'Expost' ))))) as TipoReq,
Unidad_negocios_2,
aprob_or_2.LastOfFecha_aprobac,
[SumOfOrden de Cambio_2]
FROM bases_or_con_oc
LEFT JOIN aprob_or_2 ON (N_orden = aprob_or_2.N_orden_OR)
AND (Tipo_orden = aprob_or_2.Tipo_ordenOR)
AND (N_linea = aprob_or_2.N_lineaOR)
WHERE estado_sig_2 > 110
AND (case when [Cant_recibida_2] = 0 and [Cant_pendiente_2] = 0 and [estado_sig_2] = 999 then 'Anulada'
else (case when [Cant_recibida_2] = [Cantidad_2] and [estado_sig_2] = 999 and [Tiene_OC_2] = 'SinOC'
then 'Anulada' else 'NoAnulada')) = 'noAnulada'
")
错误图片:
我也尝试排除一些行,以便找出错误点...
I also tried to exclude some lines in order to and find out the error point...
你知道发生了什么吗?
推荐答案
考虑使用 SQLite 支持的 CTE 子句 WITH()
简化您的 SQL,以避免为 重新键入相同的计算列SELECT
和 WHERE
子句中的 Anulada.并确保用 END
关闭所有 CASE
语句:
Consider simplifying your SQL using the CTE clause, WITH()
, supported by SQLite to avoid retyping same calculated column for Anulada in SELECT
and WHERE
clauses. And be sure to close all CASE
statements with END
:
WITH cte AS
(SELECT Cia_2, Nombre_cia_2, N_orden_2, Tipo_orden_2, N_linea_2, N_direc_2,
Nombre_alfa_2, Fecha_orden_2, Surtido_programado_2, Original_prometida_2,
N_orden, Tipo_orden, N_linea, Cia,
Cant_recibida_2, Cant_pENDiente_2, Cantidad_2, estado_sig_2, estado_ult_2,
CASE WHEN [N_orden_2] IS NULL THEN 'SinOC' ELSE 'ConOC' END AS TieneOC,
CASE
WHEN [Cant_recibida_2]=0 and [Cant_pENDiente_2]=0 AND [estado_sig_2] = 999
THEN 'Anulada'
ELSE
CASE
WHEN [Cant_recibida_2] = [Cantidad_2] AND [estado_sig_2] = 999 and [Tiene_OC_2] = 'SinOC'
THEN 'Anulada'
ELSE 'NoAnulada'
END
END AS Anulada,
CASE [N_direc_2]
WHEN 35999999 THEN 'Normal'
WHEN 35999998 THEN 'Urgente'
WHEN 35999997 THEN 'Emergente'
WHEN 35999995 THEN 'Proyecto'
WHEN 35999994 THEN 'Importaciones'
ELSE 'Expost'
END AS TipoReq,
Unidad_negocios_2, aprob_or_2.LastOfFecha_aprobac, [SumOfOrden de Cambio_2]
FROM bases_or_con_oc
LEFT JOIN aprob_or_2 ON (N_orden = aprob_or_2.N_orden_OR)
AND (Tipo_orden = aprob_or_2.Tipo_ordenOR)
AND (N_linea = aprob_or_2.N_lineaOR)
WHERE estado_sig_2 > 110
)
SELECT * FROM cte WHERE [Anulada] = 'NoAnulada';
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