本文介绍了xsd 如何表示不同的 xml 文件?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
如果我有这个 XML 数据主文件
if I have this XML dataMain.xml
<SigmodRecord>
<issue>
<volume>11</volume>
<number>1</number>
<articles>
<article>
<title>Annotated Bibliography on Data Design.</title>
<initPage>45</initPage>
<endPage>77</endPage>
<authors>
<author position="00">Anthony I. Wasserman</author>
<author position="01">Karen Botnich</author>
</authors>
</article>
<article>
<title>Architecture of Future Data Base Systems.</title>
<initPage>30</initPage>
<endPage>44</endPage>
<authors>
<author position="00">Lawrence A. Rowe</author>
<author position="01">Michael Stonebraker</author>
</authors>
</article>
<article>
<title>Database Directions III Workshop Review.</title>
<initPage>8</initPage>
<endPage>8</endPage>
<authors>
<author position="00">Tom Cook</author>
</authors>
</article>
<article>
<title>Errors in 'Process Synchronization in Database Systems'.</title>
<initPage>9</initPage>
<endPage>29</endPage>
<authors>
<author position="00">Philip A. Bernstein</author>
<author position="01">Marco A. Casanova</author>
<author position="02">Nathan Goodman</author>
</authors>
</article>
</articles>
</issue>
</SigmodRecord>
和这个架构 Main.xsd
and this schema Main.xsd
<?xml version="1.0" encoding="utf-16"?>
<xsd:schema attributeFormDefault="unqualified" elementFormDefault="qualified" version="1.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsd:element name="SigmodRecord">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="issue">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="volume" type="xsd:int" />
<xsd:element name="number" type="xsd:int" />
<xsd:element name="articles">
<xsd:complexType>
<xsd:sequence>
<xsd:element maxOccurs="unbounded" name="article">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="title" type="xsd:string" />
<xsd:element name="initPage" type="xsd:int" />
<xsd:element name="endPage" type="xsd:int" />
<xsd:element name="authors">
<xsd:complexType>
<xsd:sequence>
<xsd:element maxOccurs="unbounded" name="author">
<xsd:complexType>
<xsd:attribute name="position" type="xsd:int" />
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
它变成了这样的2个片段Frag1.xml:
it becomes 2 fragments like thisFrag1.xml:
<SigmodRecord>
<issue>
<volume>11</volume>
<number>1</number>
<articles>
<article>
<title>Annotated Bibliography on Data Design.</title>
<initPage>45</initPage>
<endPage>77</endPage>
</article>
<article>
<title>Architecture of Future Data Base Systems.</title>
<initPage>30</initPage>
<endPage>44</endPage>
</article>
<article>
<title>Database Directions III Workshop Review.</title>
<initPage>8</initPage>
<endPage>8</endPage>
</article>
<article>
<title>Errors in 'Process Synchronization in Database Systems'.</title>
<initPage>9</initPage>
<endPage>29</endPage>
</article>
</articles>
</issue>
</SigmodRecord>
Frag2.xml:
<SigmodRecord>
<authors>
<author position="00">Anthony I. Wasserman</author>
<author position="01">Karen Botnich</author>
</authors>
<authors>
<author position="00">Lawrence A. Rowe</author>
<author position="01">Michael Stonebraker</author>
</authors>
<authors>
<author position="00">Tom Cook</author>
</authors>
<authors>
<author position="00">Philip A. Bernstein</author>
<author position="01">Marco A. Casanova</author>
<author position="02">Nathan Goodman</author>
</authors>
</SigmodRecord>
如何使用一个可以表示两个 Fragment 的模式，同时保持第一个 XML 的原始结构.换句话说，有没有办法让 Main.xsd 代表 Frag1.xsd+frag2.xsd我不想要 2 架构只有一个！?提前致谢
how can I use one schema that can represent both of Fragments with keeping the original structure of the first XML.In other words, is there any way to make Main.xsd represent Frag1.xsd+frag2.xsdI do not want 2 schema only one!!?Thanks in advance
推荐答案
您正在寻找的架构看起来像这样，
The schema you are looking for looks something like this,
<?xml version="1.0" encoding="utf-16"?>
<xsd:schema attributeFormDefault="unqualified" elementFormDefault="qualified" version="1.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsd:element name="SigmodRecord">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="issue">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="volume" type="xsd:int" />
<xsd:element name="number" type="xsd:int" />
<xsd:element name="articles">
<xsd:complexType>
<xsd:sequence>
<xsd:element maxOccurs="unbounded" name="article">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="title" type="xsd:string" />
<xsd:element name="initPage" type="xsd:int" />
<xsd:element name="endPage" type="xsd:int" />
<xsd:element ref="authors"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:element ref="authors"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:element name="authors">
<xsd:complexType>
<xsd:sequence>
<xsd:element maxOccurs="unbounded" name="author">
<xsd:complexType>
<xsd:attribute name="position" type="xsd:int" />
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
此模式适用于所有 3 个 xml 片段.
This schema will work for all the 3 xml fragments.
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