本文介绍了如何从Oracle SQL Developer中的DateTime字段中提取时间?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我尝试过 To_Timestamp
和SQL Developer的其他方法,但只有这一个对我有用。
选择To_Number(To_Char(DateTime_FieldName,'HH24'))
|| ':'|| to_number(to_char(DateTime_FieldName,'MI'))
|| ':'|| to_number(to_char(DateTime_FieldName,'SS'))
from TABLE_NAME
是否有更好的解决方案?
解决方案
假设你的目标是生成一个代表时间的字符串(这是什么查询您发布的回报,尽管无关紧要的 to_number
调用)
SELECT to_char << column_name>>'HH24:MI:SS')
FROM table_name
如果要返回不同的数据类型,您需要告诉我们您要返回的数据类型。例如,如果您真的要返回一个 INTERVAL DAY TO SECOND
SELECT numtodsinterval(< column name>> - trunc(< column name>>),'day')
/ pre>
FROM table_name
I tried
To_Timestamp
and other methods for SQL Developer but only this one worked fine for me.Select To_Number(To_Char(DateTime_FieldName, 'HH24')) || ':' || to_number(to_char(DateTime_FieldName, 'MI')) || ':' ||to_number(to_char(DateTime_FieldName, 'SS')) from TABLE_NAME
Is there a better solution to this?
解决方案Assuming your goal is to generate a string representing the time (which is what the query you posted returns despite the extraneous
to_number
calls)SELECT to_char( <<column_name>>, 'HH24:MI:SS' ) FROM table_name
If you want to return a different data type, you'd need to tell us what data type you want to return. If, for example, you really want to return an
INTERVAL DAY TO SECOND
SELECT numtodsinterval( <<column name>> - trunc(<<column name>>), 'day' ) FROM table_name
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