本文介绍了如何编辑,修改嵌套的JSONObject的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
您能帮我解决这个问题吗?例如我有JSONEObject
Could you help me with this issue please. for example I have JSONEObject
{
"glossary": {
"title": "example glossary",
"GlossDiv": {
"title": "S",
"seeds": "12415",
}
}
}
例如,我需要将种子":"12415"更改为种子":"555".我找到了一些解决方案:
For example, I need change "seeds":"12415" to "seeds":"555".I found some solution:
JSONObject js = new JSONObject(jsonString);
js.getJSONObject("glossary").getJSONObject("GlossDiv").remove("seeds");
js.getJSONObject("glossary").getJSONObject("GlossDiv").put("seeds","555");
因此,要在我的版本中编辑种子,我需要先获取词汇表",然后获取"GlossDiv",然后再删除种子"并放入具有新值的新种子".
So for editing seeds in my version I need first to get "glossary" then "GlossDiv" after I delete "seeds" and put new "seeds" with new value.
您能帮我找到另一种编辑方式吗?例如:只是somemethod(String key,String NewValue).
Could you help me to find another way to edit? For example: just somemethod(String key,String NewValue).
推荐答案
我找到了解决方法.
public static JSONObject setProperty(JSONObject js1, String keys, String valueNew) throws JSONException {
String[] keyMain = keys.split("\\.");
for (String keym : keyMain) {
Iterator iterator = js1.keys();
String key = null;
while (iterator.hasNext()) {
key = (String) iterator.next();
if ((js1.optJSONArray(key) == null) && (js1.optJSONObject(key) == null)) {
if ((key.equals(keym))) {
js1.put(key, valueNew);
return js1;
}
}
if (js1.optJSONObject(key) != null) {
if ((key.equals(keym))) {
js1 = js1.getJSONObject(key);
break;
}
}
if (js1.optJSONArray(key) != null) {
JSONArray jArray = js1.getJSONArray(key);
for (int i = 0; i < jArray.length(); i++) {
js1 = jArray.getJSONObject(i);
}
break;
}
}
}
return js1;
}
public static void main(String[] args) throws IOException, JSONException {
FileInputStream inFile = new FileInputStream("/home/ermek/Internship/labs/java/task/test5.json");
byte[] str = new byte[inFile.available()];
inFile.read(str);
String text = new String(str);
JSONObject json = new JSONObject(text);
setProperty(json, "rpc_server_type", "555");
System.out.println(json.toString(4));
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