如何从表格测量中显示记录并在表格进度中保存相关记录

问题描述

大家好......我试图显示来自度量的记录（字段：度量，目标（主键），目标）并将记录插入进度（字段：targetid（外键），progressid（主键），进度，评论）。这种关系由targetid联系起来。请告知以下编码...非常感谢。

$ con = mysqli_connect（localhost，username，，database）;

//检查连接

if（mysqli_connect_errno （））{

echo无法连接到MySQL：。 mysqli_connect_error（）;

}

$ result = mysqli_query（$ con，SELECT Measure，target FROM target）;

echo

;



while（$ row = mysqli_fetch_array（$ result））{

echo;

echo;

echo;

echo;

}

echo

测量	目标
。 $ row ['Measure']。	。 $ row ['目标']。

;



mysqli_close（$ con）;

< ; form action =progress.phpmethod =post>

目标

进度：<输入类型= textname =progress>

评论：< input type =textname =Comment>

< input type =Submitname =Submit>

< / form>

if（isset（$ _ POST ['Submit' ]））{

$ con = mysql_connect（localhost，username，）;

if（！$ con）

{

die（'无法连接：'。mysql_error（））;

}

mysql_select_db（database，$ con） ;



//将数据放入数据库

$ sql =插入进度（进度，注释）值（'$ _POST [进度]'，'$ _ POST [评论]'）;

mysql_query（$ sql，$ con）;

mysql_close（$ con）;

}

？>

解决方案

Hi everyone...am trying to display record from measure (field:measure,targetid(primary key),target) and insert record into progress (field:targetid(foreign key),progressid(primary key),progress,comment).The relationship is linked by targetid. Please advise on the coding below...Thanks a lot.

$con=mysqli_connect("localhost","username","","database");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT Measure,target FROM target");
echo "
";

while($row = mysqli_fetch_array($result)) {
echo "";
echo "";
echo "";
echo "";
}
echo "

Measure	Target
" . $row['Measure'] . "	" . $row['Target'] . "

";

mysqli_close($con);
<form action="progress.php" method="post">

Target

Progress:<input type="text" name="progress">

Comment:<input type="text" name="Comment">

<input type="Submit" name="Submit">
</form>
if (isset($_POST['Submit'])){
$con = mysql_connect("localhost","username","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("database", $con);

//put data into database
$sql="Insert into progress (progress,Comment)values ('$_POST[progress]','$_POST[Comment]')";
mysql_query($sql,$con);
mysql_close($con);
}
?>

解决方案

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