问题描述
我已经阅读了很多C#值对象的示例,并且我了解它是一个由其值标识的对象".如果值更改,则该对象为新".
但是,当涉及到PHP时,这似乎没有任何意义……要么就是我没有建立连接.
值对象仅仅是字符串吗?
将其置于上下文中,在许多OO语言中,对象通过其 identity 进行比较.用伪代码:
bar = new Foo
baz = new Foo
bar == baz // false
即使您仅查看它们的值,即使这两个对象基本相同,但由于它们是单独的实例,因此也不认为它们是相同的.演示:
bar = new Foo
baz = bar
bar == baz // true
现在:
这将是值对象"的演示:
address1 = new Address('Main street 42')
address2 = new Address('Main street 42')
address1 == address2 // true
由于值相同,因此即使它们是单独的实例,两个对象也被视为相等.
PHP没有单独的值对象"概念,它只有一种类型的对象.它的比较运算符可以做到这一点:例如:
$address1 = new Address('Main street 42');
$address2 = new Address('Main street 42');
$address1 == $address2; // true equal...
$address1 === $address2; // false ...but not identical
I have read plenty of C# examples of Value Objects, and I understand that it is an "object" that is identified by it's values. If a value changes, the object is "new".
However, that doesn't seem to make sense when it comes to PHP...either that, or I'm just not making the connection.
Is a Value Object just a string?
To put this into context, in many OO languages, objects are compared by their identity. In pseudocode:
bar = new Foo
baz = new Foo
bar == baz // false
Even though both objects are basically the same if you just look at their values, they're not considered to be identical, because they are separate instances. To demonstrate:
bar = new Foo
baz = bar
bar == baz // true
Now:
This would be a demonstration of "value objects":
address1 = new Address('Main street 42')
address2 = new Address('Main street 42')
address1 == address2 // true
Because the values are the same, both objects are considered equal, even if they're separate instances.
PHP does not have a separate concept of "value objects", it only has one type of object. Its comparison operator can make that distinction though:
E.g.:
$address1 = new Address('Main street 42');
$address2 = new Address('Main street 42');
$address1 == $address2; // true equal...
$address1 === $address2; // false ...but not identical
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