问题描述
我无法在JPA 2 / Hibernate中使用复合主键和外键。我正在尝试为国家和省份创建一个简单的场景:
I'm having trouble getting a composite primary key and foreign keys working in JPA 2/Hibernate. I'm trying to create a simple scenario with countries and provinces:
国家/地区实体:
@Entity
@Table(name = "country")
public class Country extends DomainObjectBase implements Serializable {
@Id
@Basic(optional = false)
@Column(name = "code")
private String code;
@Basic(optional = false)
@Column(name = "name")
private String name;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "country")
private List<Province> provinces;
}
省主键:
@Embeddable
public class ProvincePK implements Serializable {
@Basic(optional = false)
@Column(name = "code")
private String code;
@Basic(optional = false)
@Column(name = "country_code")
private String countryCode;
}
省实体:
@Entity
@Table(name = "province")
public class Province extends DomainObjectBase implements Serializable {
@EmbeddedId
protected ProvincePK provincePK;
@Basic(optional = false)
@Column(name = "name")
private String name;
@MapsId("country_code")
@JoinColumn(name = "country_code", referencedColumnName = "code", insertable = false, updatable = false)
@ManyToOne(optional = false)
private Country country;
}
这为我创建了正确的表格,但有一个例外:
This create the correct tables for me with one exception:
国家表:
- 代码PK
- name
省表
- 代码PK FK - 这就是问题是它创建国家表的代码列的外键引用
- country_code FK 这是我想要的唯一外键引用
- name
如何为hibernate映射我的实体/复合键生成我想要的架构?现在我不能将任何数据插入省,因为它期望该国家/地区包含省代码!
How do I map my entities/composite key for hibernate to generate the schema I want? Right now I can't insert any data into province because its expecting that country contains the province code!
感谢您的帮助。
推荐答案
试试这个。我发现当我处理这样的数据模型时,它对我有用。
Try this. I've found that it works for me when I work with data models like this.
@Entity
@Table(name = "province")
@IdClass(ProvincePK.class)
public class Province extends DomainObjectBase implements Serializable {
@Id
@Basic(optional = false)
@Column(name = "code")
private String code;
@Id
@Basic(optional = false, insertable = false, updatable = false)
@Column(name = "country_code")
private String countryCode;
@Basic(optional = false)
@Column(name = "name")
private String name;
@JoinColumn(name = "country_code", referencedColumnName = "code")
@ManyToOne
private Country country;
}
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