JPA复合键+序列

问题描述

在纯JPA或JPA + Hibernate扩展中，是否可以声明组合键，其中组合键的元素是序列？

这是我的合成class：

  @Embeddable 
 public class IntegrationEJBPk实现了Serializable {
 
 // .. 。
 
 
 @ManyToOne（cascade = {}，fetch = FetchType.EAGER）
 @JoinColumn（name =APPLICATION）
 public ApplicationEJB getApplication（）{ 
返回应用程序; 
 
 
 $ b @Column（name =ENTITY，unique = false，nullable = false，insertable = true，updatable = true）
 public String getEntity ）{
返回实体; 
} 
 
 @GeneratedValue（strategy = GenerationType.AUTO，generator =INTEGRATION_ID_GEN）
 @SequenceGenerator（name =INTEGRATION_ID_GEN，sequenceName =OMP_INTEGRATION_CANONICAL_SEQ）
 @Column（name =CANONICAL_ID，unique = false，nullable = false，insertable = true，updatable = true）
 public String getCanonicalId（）{
 return canonicalId; 
 
 
 @Column（name =NATIVE_ID，unique = false，nullable = false，insertable = true，updatable = true）
 public String getNativeId（）{
返回nativeId; 
 
 
 @Column（name =NATIVE_KEY，unique = false，nullable = false，insertable = true，updatable = true）
 public String getNativeKey（）{
返回nativeKey; 
} 
 
 // ... 
} 
  

我已经为应用程序，实体， nativeId 和 nativeKey 。我想构建一个如下所示的实体：



  IntegrationEJB i1 = new IntegrationEJB（）; 
 i1.setIntegrationId（new IntegrationEJBPk（））; 
 i1.getIntegrationId（）。setApplication（app1）; 
 i1.getIntegrationId（）。setEntity（Entity）; 
 i1.getIntegrationId（）。setNativeId（Nid）; 
 i1.getIntegrationId（）。setNativeKey（NK）; 
  

当我调用 em.persist（i1 ），我希望生成 canonicalId 并且插入集成。

这可能吗？如果是这样，那么简单的方法是什么？ （我更喜欢不使用应用程序提供的键或本机sql）。 我相信这对于普通的JPA来说是不可能的。

Is it possible in plain JPA or JPA+Hibernate extensions to declare a composite key, where an element of the composite key is a sequence?

This is my composite class:

@Embeddable
public class IntegrationEJBPk implements Serializable {

    //...


    @ManyToOne(cascade = {}, fetch = FetchType.EAGER)
    @JoinColumn(name = "APPLICATION")
    public ApplicationEJB getApplication() {
        return application;
    }


    @Column(name = "ENTITY", unique = false, nullable = false, insertable = true, updatable = true)
    public String getEntity() {
        return entity;
    }

    @GeneratedValue(strategy = GenerationType.AUTO, generator = "INTEGRATION_ID_GEN")
    @SequenceGenerator(name = "INTEGRATION_ID_GEN", sequenceName = "OMP_INTEGRATION_CANONICAL_SEQ")
    @Column(name = "CANONICAL_ID", unique = false, nullable = false, insertable = true, updatable = true)
    public String getCanonicalId() {
        return canonicalId;
    }

    @Column(name = "NATIVE_ID", unique = false, nullable = false, insertable = true, updatable = true)
    public String getNativeId() {
        return nativeId;
    }

    @Column(name = "NATIVE_KEY", unique = false, nullable = false, insertable = true, updatable = true)
    public String getNativeKey() {
        return nativeKey;
    }

    //...
}

I already supply the values for application, entity, nativeId and nativeKey. I want to construct an entity like the one below:

IntegrationEJB i1 = new IntegrationEJB();
i1.setIntegrationId(new IntegrationEJBPk());
i1.getIntegrationId().setApplication(app1);
i1.getIntegrationId().setEntity("Entity");
i1.getIntegrationId().setNativeId("Nid");
i1.getIntegrationId().setNativeKey("NK");

And when I call em.persist(i1), I want that the canonicalId is generated and the integration is inserted.

Is this possible? If so, what's the simple way? (I prefer not to use application-provided keys or native sql).

解决方案

I believe that this is not possible with plain JPA.

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